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Sinar X dengan panjang gelombang 0 , 1 A ˚ mengalami hamburan Compton pada sudut 6 0 ∘ , hitunglah momentum elektron tertolak!

Sinar X dengan panjang gelombang  mengalami hamburan Compton pada sudut , hitunglah momentum elektron tertolak!

Y. Maghfirah

Master Teacher

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Jawaban

momentum elektron yang tertolak sebesar .

momentum elektron yang tertolak sebesar begin mathsize 14px style 6 comma 24 cross times 10 to the power of negative 23 end exponent space kg. straight m divided by straight s end style.

Pembahasan

Perubahan panjang gelombang sinar X setelah hamburan sebesar; Energi kinetik elektron tertolak merupakan selisih energi foton datang dengan foton terhambur. Sehingga momentum; Dengan demikian, momentum elektron yang tertolak sebesar .

Perubahan panjang gelombang sinar X setelah hamburan sebesar;

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell lambda apostrophe minus lambda end cell equals cell fraction numerator h over denominator m subscript 0 c end fraction left parenthesis 1 minus cos open parentheses theta close parentheses right parenthesis end cell row cell increment lambda end cell equals cell fraction numerator 6 comma 626 cross times 10 to the power of negative 34 end exponent over denominator left parenthesis 9 comma 1 cross times 10 to the power of negative 31 end exponent right parenthesis left parenthesis 3 cross times 10 to the power of 8 right parenthesis end fraction left parenthesis 1 minus cos open parentheses 60 close parentheses right parenthesis end cell row blank equals cell 2 comma 43 cross times 10 to the power of negative 12 end exponent left parenthesis 1 minus 1 half right parenthesis end cell row blank equals cell 1 comma 21 cross times 10 to the power of negative 12 end exponent space straight m end cell end table end style 

Energi kinetik elektron tertolak merupakan selisih energi foton datang dengan foton terhambur.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell E subscript K end cell equals cell fraction numerator h c over denominator lambda subscript 0 end fraction minus fraction numerator h c over denominator lambda apostrophe end fraction end cell row blank equals cell fraction numerator h c over denominator lambda subscript 0 end fraction minus fraction numerator h c over denominator lambda subscript 0 plus increment lambda end fraction end cell row blank equals cell fraction numerator 6 comma 626 cross times 10 to the power of negative 34 end exponent left parenthesis 3 cross times 10 to the power of 8 right parenthesis over denominator 1 cross times 10 to the power of negative 11 end exponent end fraction minus fraction numerator 6 comma 626 cross times 10 to the power of negative 34 end exponent left parenthesis 3 cross times 10 to the power of 8 right parenthesis over denominator open parentheses 1 cross times 10 to the power of negative 11 end exponent plus 1 comma 21 cross times 10 to the power of negative 12 end exponent close parentheses end fraction end cell row blank equals cell 2 comma 14 cross times 10 to the power of negative 15 end exponent space straight J end cell end table end style

Sehingga momentum;

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row p equals cell square root of 2 m E subscript K end root end cell row blank equals cell square root of 2 open parentheses 9 comma 1 cross times 10 to the power of negative 31 end exponent close parentheses open parentheses 2 comma 14 cross times 10 to the power of negative 15 end exponent close parentheses end root end cell row blank equals cell square root of 38 comma 948 cross times 10 to the power of negative 46 end exponent end root end cell row blank equals cell 6 comma 24 cross times 10 to the power of negative 23 end exponent space kg. straight m divided by straight s end cell end table end style 

Dengan demikian, momentum elektron yang tertolak sebesar begin mathsize 14px style 6 comma 24 cross times 10 to the power of negative 23 end exponent space kg. straight m divided by straight s end style.

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