Roboguru

Sinar X dengan panjang gelombang  mengalami hamburan Compton pada sudut , hitunglah energi elektron tertolak!

Pertanyaan

Sinar X dengan panjang gelombang begin mathsize 14px style 0 comma 1 space straight Å end style mengalami hamburan Compton pada sudut begin mathsize 14px style 60 degree end style, hitunglah energi elektron tertolak!

Pembahasan Soal:

Perubahan panjang gelombang sinar X setelah hamburan sebesar;

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell lambda apostrophe minus lambda end cell equals cell fraction numerator h over denominator m subscript 0 c end fraction left parenthesis 1 minus cos open parentheses theta close parentheses right parenthesis end cell row cell increment lambda end cell equals cell fraction numerator 6 comma 626 cross times 10 to the power of negative 34 end exponent over denominator left parenthesis 9 comma 1 cross times 10 to the power of negative 31 end exponent right parenthesis left parenthesis 3 cross times 10 to the power of 8 right parenthesis end fraction left parenthesis 1 minus cos open parentheses 60 close parentheses right parenthesis end cell row blank equals cell 2 comma 43 cross times 10 to the power of negative 12 end exponent left parenthesis 1 minus 1 half right parenthesis end cell row blank equals cell 1 comma 21 cross times 10 to the power of negative 12 end exponent space straight m end cell end table end style 

Energi kinetik elektron tertolak merupakan selisih energi foton datang dengan foton terhambur.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell E subscript K end cell equals cell fraction numerator h c over denominator lambda subscript 0 end fraction minus fraction numerator h c over denominator lambda apostrophe end fraction end cell row blank equals cell fraction numerator h c over denominator lambda subscript 0 end fraction minus fraction numerator h c over denominator lambda subscript 0 plus increment lambda end fraction end cell row blank equals cell fraction numerator 6 comma 626 cross times 10 to the power of negative 34 end exponent left parenthesis 3 cross times 10 to the power of 8 right parenthesis over denominator 1 cross times 10 to the power of negative 11 end exponent end fraction minus fraction numerator 6 comma 626 cross times 10 to the power of negative 34 end exponent left parenthesis 3 cross times 10 to the power of 8 right parenthesis over denominator open parentheses 1 cross times 10 to the power of negative 11 end exponent plus 1 comma 21 cross times 10 to the power of negative 12 end exponent close parentheses end fraction end cell row blank equals cell 2 comma 14 cross times 10 to the power of negative 15 end exponent space straight J end cell end table end style 

Dengan demikian, energi kinetik yang tertolak sebesar begin mathsize 14px style 2 comma 14 cross times 10 to the power of negative 15 end exponent space straight J end style.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 14 Maret 2021

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