Sinar X dengan panjang gelombang mengalami hamburan Compton pada sudut , hitunglah energi elektron tertolak!

Pertanyaan

Sinar X dengan panjang gelombang $begin mathsize 14px style 0 comma 1 space straight Å end style$ mengalami hamburan Compton pada sudut $begin mathsize 14px style 60 degree end style$ , hitunglah energi elektron tertolak!

Pembahasan Soal:

Perubahan panjang gelombang sinar X setelah hamburan sebesar;

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell lambda apostrophe minus lambda end cell equals cell fraction numerator h over denominator m subscript 0 c end fraction left parenthesis 1 minus cos open parentheses theta close parentheses right parenthesis end cell row cell increment lambda end cell equals cell fraction numerator 6 comma 626 cross times 10 to the power of negative 34 end exponent over denominator left parenthesis 9 comma 1 cross times 10 to the power of negative 31 end exponent right parenthesis left parenthesis 3 cross times 10 to the power of 8 right parenthesis end fraction left parenthesis 1 minus cos open parentheses 60 close parentheses right parenthesis end cell row blank equals cell 2 comma 43 cross times 10 to the power of negative 12 end exponent left parenthesis 1 minus 1 half right parenthesis end cell row blank equals cell 1 comma 21 cross times 10 to the power of negative 12 end exponent space straight m end cell end table end style$

Energi kinetik elektron tertolak merupakan selisih energi foton datang dengan foton terhambur.

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell E subscript K end cell equals cell fraction numerator h c over denominator lambda subscript 0 end fraction minus fraction numerator h c over denominator lambda apostrophe end fraction end cell row blank equals cell fraction numerator h c over denominator lambda subscript 0 end fraction minus fraction numerator h c over denominator lambda subscript 0 plus increment lambda end fraction end cell row blank equals cell fraction numerator 6 comma 626 cross times 10 to the power of negative 34 end exponent left parenthesis 3 cross times 10 to the power of 8 right parenthesis over denominator 1 cross times 10 to the power of negative 11 end exponent end fraction minus fraction numerator 6 comma 626 cross times 10 to the power of negative 34 end exponent left parenthesis 3 cross times 10 to the power of 8 right parenthesis over denominator open parentheses 1 cross times 10 to the power of negative 11 end exponent plus 1 comma 21 cross times 10 to the power of negative 12 end exponent close parentheses end fraction end cell row blank equals cell 2 comma 14 cross times 10 to the power of negative 15 end exponent space straight J end cell end table end style$

Dengan demikian, energi kinetik yang tertolak sebesar $begin mathsize 14px style 2 comma 14 cross times 10 to the power of negative 15 end exponent space straight J end style$ .

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 14 Maret 2021

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