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Seratus mL larutan NH 4 ​ OH 0 , 1 M mempunyai pH sama dengan 100 mL larutan Ca ( OH ) 2 ​ 5 × 1 0 − 4 M . K b ​ NH 4 ​ OH adalah ...

Seratus mL larutan  mempunyai pH sama dengan  larutan  adalah...

  1. begin mathsize 14px style 1 comma 8 cross times 10 to the power of negative sign 5 end exponent end style 

  2. begin mathsize 14px style 1 cross times 10 to the power of negative sign 5 end exponent end style 

  3. begin mathsize 14px style 1 comma 8 cross times 10 to the power of negative sign 3 end exponent end style 

  4. begin mathsize 14px style 1 cross times 10 to the power of negative sign 3 end exponent end style 

  5. begin mathsize 14px style 1 comma 8 cross times 10 to the power of negative sign 2 end exponent end style 

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Jawaban terverifikasi

Jawaban

jawaban yang benar adalah B.

jawaban yang benar adalahspaceB.

Pembahasan

Pembahasan
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Ketika pH = pH , maka: Menghitung : adalah basa kuat karena terionisasi sempurna di dalam larutan → Ca 2 + + 2 OH − Menghitung : Jadi, jawaban yang benar adalah B.

Ketika pH N H subscript 4 O H = pH Ca open parentheses O H close parentheses subscript 2, maka:

open square brackets O H to the power of minus sign close square brackets space N H subscript 4 O H equals open square brackets O H to the power of minus sign close square brackets space Ca open parentheses O H close parentheses subscript 2

  • Menghitung open square brackets O H to the power of minus sign close square brackets space Ca open parentheses O H close parentheses subscript 2:
    Ca open parentheses O H close parentheses subscript 2 adalah basa kuat karena terionisasi sempurna di dalam larutan
    Ca open parentheses O H close parentheses subscript 2 

table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell M cross times b end cell row blank equals cell 5 cross times 10 to the power of negative sign 4 end exponent cross times 2 end cell row blank equals cell 10 to the power of negative sign 3 end exponent end cell end table 

 

  • open square brackets O H to the power of minus sign close square brackets space N H subscript 4 O H equals open square brackets O H to the power of minus sign close square brackets space Ca open parentheses O H close parentheses subscript 2 equals 10 to the power of negative sign 3 end exponent 
  • Menghitung K subscript b space N H subscript 4 O H:

table attributes columnalign right center left columnspacing 0px end attributes row cell left square bracket O H to the power of minus sign right square bracket end cell equals cell square root of K subscript b cross times M end root end cell row cell 1 cross times 10 to the power of negative sign 3 end exponent end cell equals cell square root of K subscript b cross times 1 cross times 10 to the power of negative sign 1 end exponent end root end cell row cell left parenthesis 1 cross times 10 to the power of negative sign 3 end exponent right parenthesis squared end cell equals cell left parenthesis square root of K subscript b cross times 1 cross times 10 to the power of negative sign 1 end exponent end root right parenthesis squared end cell row cell 1 cross times 10 to the power of negative sign 6 end exponent end cell equals cell K subscript b cross times 1 cross times 10 to the power of negative sign 1 end exponent end cell row cell K subscript b end cell equals cell fraction numerator 1 cross times 10 to the power of negative sign 6 end exponent over denominator 1 cross times 10 to the power of negative sign 1 end exponent end fraction end cell row cell K subscript b end cell equals cell 1 cross times 10 to the power of negative sign 5 end exponent end cell end table 
 

Jadi, jawaban yang benar adalahspaceB.

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