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Senyawa H 2 ​ C 2 ​ O 4 ​ ⋅ xH 2 ​ O sebanyak 12,6 gram dipanaskan dan beratnya berkurang 3,6 gram. Rumus hidrat tersebutadalah.… (Ar, C=32, O=16, H=1)

Senyawa  sebanyak 12,6 gram dipanaskan dan beratnya berkurang 3,6 gram. Rumus hidrat tersebut adalah.… (Ar, C=32, O=16, H=1)

  1. straight H subscript 2 straight C subscript 2 straight O subscript 4 space times space straight H subscript 2 straight O space

  2. straight H subscript 2 straight C subscript 2 straight O subscript 4 space times space 2 straight H subscript 2 straight O

  3. straight H subscript 2 straight C subscript 2 straight O subscript 4 space times space 3 straight H subscript 2 straight O

  4. straight H subscript 2 straight C subscript 2 straight O subscript 4 space times space 4 straight H subscript 2 straight O

  5. straight H subscript 2 straight C subscript 2 straight O subscript 4 space times space 5 straight H subscript 2 straight O

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S. Susanti

Master Teacher

Mahasiswa/Alumni Universitas Jayabaya

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rumus senyawa hidrat tersebutadalah

rumus senyawa hidrat tersebut adalah straight H subscript 2 straight C subscript 2 straight O subscript 4 space times space 2 straight H subscript 2 straight O   

Pembahasan

Massa kristal hidrat = 12,6 gram Massa air = 3,6 gram Massa kristal anhidrat = 12,6 – 3,6 = 9 gram Maka, nilai x adalah 2. Jadi rumus senyawa hidrat tersebutadalah

Massa kristal hidrat = 12,6 gram

Massa air = 3,6 gram

Massa kristal anhidrat = 12,6 – 3,6 = 9 gram

Mr space straight H subscript 2 straight C subscript 2 straight O subscript 4 space end subscript equals space open parentheses 2 cross times Ar space straight H close parentheses plus open parentheses 2 cross times Ar space straight C close parentheses plus open parentheses 4 cross times Ar space straight O close parentheses space space space space space space space space space space space space space space space space space space space space space equals space open parentheses 2 cross times 1 close parentheses plus open parentheses 2 cross times 12 close parentheses plus open parentheses 4 cross times 16 close parentheses space space space space space space space space space space space space space space space space space space space space space equals 2 plus 24 plus 64 space space space space space space space space space space space space space space space space space space space space space equals 90 space gram divided by mol Mr space straight H subscript 2 straight O subscript space space space space space space space space equals space open parentheses 2 cross times Ar space straight H close parentheses plus open parentheses 1 cross times Ar space straight O close parentheses space space space space space space space space space space space space space space space space space space space space space equals space open parentheses 2 cross times 1 close parentheses plus open parentheses 1 cross times 16 close parentheses space space space space space space space space space space space space space space space space space space space space space equals 18 space gram divided by mol

 

straight H subscript 2 straight C subscript 2 straight O subscript 4 times xH subscript 2 straight O space rightwards arrow space space space space straight H subscript 2 straight C subscript 2 straight O subscript 4 space space space space space space plus space space space space space space space space xH subscript 2 straight O 12 comma 6 space gram space space space space space space space space space space space space space space space space space space space 9 space gram space space space space space space space space space space space space space space space 3 comma 6 space gram  space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space fraction numerator 9 space gram over denominator M r space H subscript 2 C subscript 2 O subscript 4 space end fraction space space space space space fraction numerator 3 comma 6 space gram over denominator M r space H subscript 2 O end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space fraction numerator 9 space gram over denominator 90 space end fraction space space space space space space space space space space space space space fraction numerator 3 comma 6 space gram over denominator 18 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space 0 comma 1 space space space space space space space space space space space space space space space space space space space space space space space space 0 comma 2 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space 1 space space space space space space space space space space space space space space space space space space space space space space space space space space space space 2

Maka, nilai x adalah 2. Jadi rumus senyawa hidrat tersebut adalah straight H subscript 2 straight C subscript 2 straight O subscript 4 space times space 2 straight H subscript 2 straight O   

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Muhhamad Ervan

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Sebanyak 2,1 gram kristal MgSO 4 ​ ⋅ xH 2 ​ O dipanaskan sehingga seluruh kandungan air kristal menguap.Jika berat setelah pemanasan adalah 1,2 gram maka nilai x adalah.… (Ar Mg = 24; S = 32; O = 6; H...

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