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Sebanyak 2,1 gram kristal MgSO 4 ​ ⋅ xH 2 ​ O dipanaskan sehingga seluruh kandungan air kristal menguap.Jika berat setelah pemanasan adalah 1,2 gram maka nilai x adalah.… (Ar Mg = 24; S = 32; O = 6; H = 1)

Sebanyak 2,1 gram kristal  dipanaskan sehingga seluruh kandungan air kristal menguap. Jika berat setelah pemanasan adalah 1,2 gram maka nilai x adalah.… (Ar Mg = 24; S = 32; O = 6; H = 1)

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S. Susanti

Master Teacher

Mahasiswa/Alumni Universitas Jayabaya

Jawaban terverifikasi

Jawaban

senyawa hidratnya adalah

senyawa hidratnya adalah MgSO subscript 4 times 5 straight H subscript 2 straight O

Pembahasan

Massa kristal hidrat = 2,1 gram Massa kristal anhidrat = 1,2 gram Massa air = 2,1 – 1,2 = 0,9 gram Maka, nilai x adalah 5. Jadi senyawa hidratnya adalah

Massa kristal hidrat = 2,1 gram

Massa kristal anhidrat = 1,2 gram

Massa air = 2,1 – 1,2 = 0,9 gram

Mr space MgSO subscript 4 space equals space open parentheses 1 cross times Ar space Mg close parentheses plus open parentheses 1 cross times Ar space straight S close parentheses plus open parentheses 4 cross times Ar space straight O close parentheses space space space space space space space space space space space space space space space space space space space space equals space open parentheses 1 cross times 24 close parentheses plus open parentheses 1 cross times 32 close parentheses plus open parentheses 4 cross times 16 close parentheses space space space space space space space space space space space space space space space space space space space space equals space 24 plus 32 plus 64 space space space space space space space space space space space space space space space space space space space space equals 120 space gram divided by mol  Mr space straight H subscript 2 straight O space equals space open parentheses 2 cross times Ar space straight H close parentheses space plus open parentheses 1 cross times Ar space straight O close parentheses space space space space space space space space space space space space space space space equals space open parentheses 2 cross times 1 close parentheses plus open parentheses 1 cross times 16 close parentheses space space space space space space space space space space space space space space space equals space 18 space gram divided by mol

M g S O subscript 4 times x H subscript 2 straight O space rightwards arrow space space space space space space space space space space space space space space space MgSO subscript 4 space space space space space space space space space space space space space space space space space plus space space space space space space space space space space space space space xH subscript 2 straight O 2 comma 1 space gram space space space space space space space space space space space space space space space space space space space space space space space space space space space space fraction numerator 1 comma 2 space gram over denominator M r space M g S O subscript 4 end fraction space space space space space space space space space space space space space space space space space space space space space fraction numerator 0 comma 9 space gram over denominator M r space H subscript 2 O end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space fraction numerator 1 comma 2 space gram over denominator 120 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space fraction numerator 0 comma 9 space gram over denominator 18 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space 0 comma 01 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space 0 comma 05 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space 1 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space 5

Maka, nilai x adalah 5. Jadi senyawa hidratnya adalah MgSO subscript 4 times 5 straight H subscript 2 straight O

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Senyawa H 2 ​ C 2 ​ O 4 ​ ⋅ xH 2 ​ O sebanyak 12,6 gram dipanaskan dan beratnya berkurang 3,6 gram. Rumus hidrat tersebutadalah.… (Ar, C=32, O=16, H=1)

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