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Pertanyaan

Selesaikanlah. f. 5 x − 1 ​ − 3 x − 2 ​ > x − 1 ​

Selesaikanlah.

f.

  1. ... space 

  2. ... space 

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A. Septianingsih

Master Teacher

Mahasiswa/Alumni Universitas Gadjah Mada

Jawaban terverifikasi

Jawaban

daerah penyelesaian akhir adalah

daerah penyelesaian akhir adalah begin mathsize 14px style 1 less or equal than x less than 2 end style 

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Pembahasan

Langkah 1 : Menentukan daerah penyelesaian 1 Daerah penyelesaian : Langkah 2 : Mentukan daerah syarat akar Jadi daerah penyelesaian akhir adalah

Langkah 1 : Menentukan daerah penyelesaian 1

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell square root of 5 x minus 1 end root end cell greater than cell square root of x minus 1 end root plus square root of 3 x minus 2 end root space kuadratkan space kedua space ruas end cell row cell 5 x minus 1 end cell greater than cell x minus 1 plus 3 x minus 2 plus 2 square root of open parentheses x minus 1 close parentheses open parentheses 3 x minus 2 close parentheses end root end cell row cell 5 x minus 1 end cell greater than cell 4 x minus 3 plus 2 square root of open parentheses x minus 1 close parentheses open parentheses 3 x minus 2 close parentheses end root end cell row cell x plus 2 end cell greater than cell 2 square root of open parentheses x minus 1 close parentheses open parentheses 3 x minus 2 close parentheses end root space kuadratkan space kedua space ruas end cell row cell x squared plus 4 x plus 4 end cell greater than cell 4 open parentheses x minus 1 close parentheses open parentheses 3 x minus 2 close parentheses end cell row cell x squared plus 4 x plus 4 end cell greater than cell 4 open parentheses 3 x squared minus 5 x plus 2 close parentheses end cell row cell x squared plus 4 x plus 4 end cell greater than cell 12 x squared minus 20 x plus 8 end cell row 0 greater than cell 11 x squared minus 24 x plus 4 end cell row 0 greater than cell open parentheses 11 x minus 2 close parentheses open parentheses x minus 2 close parentheses end cell end table end style 

Daerah penyelesaian :

Langkah 2 : Mentukan daerah syarat akar

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell square root of 5 x minus 1 end root end cell greater or equal than 0 row cell 5 x minus 1 end cell greater or equal than 0 row cell 5 x end cell greater or equal than 1 row x greater or equal than cell 1 fifth end cell row blank blank blank row cell square root of 3 x minus 2 end root end cell greater or equal than 0 row cell 3 x minus 2 end cell greater or equal than 0 row cell 3 x end cell greater or equal than 2 row x greater or equal than cell 2 over 3 end cell row blank blank blank row cell square root of x minus 1 end root end cell greater or equal than 0 row cell x minus 1 end cell greater or equal than 0 row x greater or equal than 1 end table end style 

 

Jadi daerah penyelesaian akhir adalah begin mathsize 14px style 1 less or equal than x less than 2 end style 

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