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Selembar kawat berarus listrik dilengkungkan seper...

Selembar kawat berarus listrik dilengkungkan seperti pada di gambar. Jika jari-jai kelengkungan sebesar 50 cm, maka besarnya induksi magnetik di pusat lengkungan adalah .... left parenthesis mu subscript o equals space 4 straight pi.10 to the power of negative 7 end exponent. Wb. straight A to the power of negative 1 end exponent straight m to the power of negative 1 end exponent right parenthesis

  1. 1 third straight pi space. space 10 to the power of negative 7 end exponent straight T

  2. 1 space. space 10 to the power of negative 7 end exponent T

  3. straight pi space. space 10 to the power of negative 7 end exponent T

  4. 2 space. space 10 to the power of negative 7 end exponent T

  5. 2 straight pi. space 10 to the power of negative 7 end exponent T

Jawaban:

straight I equals 1 comma 5 space straight A  straight a equals 50 space cm equals 0 comma 5 space straight m

Maka besarnya induksi magnetik di titik O adalah:

B space equals space fraction numerator 120 degree over denominator 360 degree end fraction x fraction numerator space mu subscript o I over denominator 2 a end fraction  B equals space 1 third x fraction numerator left parenthesis 4 πx 10 to the power of negative 7 end exponent right parenthesis left parenthesis 1 comma 5 right parenthesis over denominator left parenthesis 2 right parenthesis left parenthesis 0 comma 5 right parenthesis end fraction  B equals 1 third x fraction numerator 6 straight pi space straight x 10 to the power of negative 7 end exponent over denominator 1 end fraction  B space equals space 2 straight pi space straight x space 10 to the power of negative 7 end exponent straight T

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