Pertanyaan

Sederhanakanlah. d. ( a 0 c − 6 a − 4 b 3 c − 1 ) − 3

Sederhanakanlah.

d. $(\frac{a ^{- 4} b ^{3} c ^{- 1}}{a ^{0} c ^{- 6}})^{- 3}$

Y. Fathoni

Master Teacher

Mahasiswa/Alumni Universitas Negeri Yogyakarta.

Jawaban terverifikasi

Jawaban

diperoleh bentuk sederhananya adalah .

diperoleh bentuk sederhananya adalah $open parentheses fraction numerator a to the power of negative 4 end exponent space b cubed space c to the power of negative 1 end exponent over denominator a to the power of 0 space c to the power of negative 6 end exponent end fraction close parentheses to the power of negative 3 end exponent equals fraction numerator a to the power of 12 over denominator b to the power of 9 c to the power of 15 end fraction$ .

Pembahasan

Ingat kembali konsep bilangan berpangkat. Akan ditentukan bentuk sederhana dari . Jadi, diperoleh bentuk sederhananya adalah .

Ingat kembali konsep bilangan berpangkat.

Akan ditentukan bentuk sederhana dari $open parentheses fraction numerator a to the power of negative 4 end exponent space b cubed space c to the power of negative 1 end exponent over denominator a to the power of 0 space c to the power of negative 6 end exponent end fraction close parentheses to the power of negative 3 end exponent$ .

$table attributes columnalign right center left columnspacing 2px end attributes row cell open parentheses fraction numerator a to the power of negative 4 end exponent space b cubed space c to the power of negative 1 end exponent over denominator a to the power of 0 space c to the power of negative 6 end exponent end fraction close parentheses to the power of negative 3 end exponent end cell equals cell open parentheses a to the power of negative 4 end exponent space b cubed space c to the power of negative 1 end exponent close parentheses to the power of negative 3 end exponent over open parentheses a to the power of 0 space c to the power of negative 6 end exponent close parentheses to the power of negative 3 end exponent end cell row blank equals cell fraction numerator open parentheses a to the power of negative 4 end exponent close parentheses to the power of negative 3 end exponent space open parentheses b cubed close parentheses to the power of negative 3 end exponent space open parentheses c to the power of negative 1 end exponent close parentheses to the power of negative 3 end exponent over denominator open parentheses a to the power of 0 close parentheses to the power of negative 3 end exponent space open parentheses c to the power of negative 6 end exponent close parentheses to the power of negative 3 end exponent end fraction end cell row blank equals cell fraction numerator a to the power of negative 4 cross times open parentheses negative 3 close parentheses end exponent b to the power of 3 cross times open parentheses negative 3 close parentheses end exponent c to the power of negative 1 cross times open parentheses negative 3 close parentheses end exponent over denominator a to the power of 0 cross times open parentheses negative 3 close parentheses end exponent c to the power of negative 6 cross times open parentheses negative 3 close parentheses end exponent end fraction end cell row blank equals cell fraction numerator a to the power of 12 b to the power of negative 9 end exponent c cubed over denominator a to the power of 0 c to the power of 18 end fraction end cell row blank equals cell a to the power of 12 over a to the power of 0 times b to the power of negative 9 end exponent times c cubed over c to the power of 18 end cell row blank equals cell a to the power of 12 over 1 times 1 over b to the power of 9 times c to the power of 3 minus 18 end exponent end cell row blank equals cell a to the power of 12 times 1 over b to the power of 9 times c to the power of negative 15 end exponent end cell row blank equals cell a to the power of 12 times 1 over b to the power of 9 times 1 over c to the power of 15 end cell row blank equals cell fraction numerator a to the power of 12 over denominator b to the power of 9 c to the power of 15 end fraction end cell end table$

Jadi, diperoleh bentuk sederhananya adalah $open parentheses fraction numerator a to the power of negative 4 end exponent space b cubed space c to the power of negative 1 end exponent over denominator a to the power of 0 space c to the power of negative 6 end exponent end fraction close parentheses to the power of negative 3 end exponent equals fraction numerator a to the power of 12 over denominator b to the power of 9 c to the power of 15 end fraction$ .