Iklan

Iklan

Pertanyaan

Sederhanakanlah: a. 4 n 4 n + 1 − 2 2 n + 1 ​

Sederhanakanlah:

a.

Iklan

N. Puspita

Master Teacher

Jawaban terverifikasi

Jawaban

hasil dari adalah .

hasil dari fraction numerator 4 to the power of n plus 1 end exponent minus 2 to the power of 2 n plus 1 end exponent over denominator 4 to the power of n end fraction adalah table attributes columnalign right center left columnspacing 0px end attributes row blank blank 2 end table.

Iklan

Pembahasan

Pembahasan
lock

Ingat kembali: Pertama mengubah menjadi bilangan berpangkat sebagai berikut. Kemudian, diperoleh perhitungan: Jadi, hasil dari adalah .

Ingat kembali:

a to the power of n equals stack stack a cross times a cross times a cross times... cross times a with underbrace below with a space s e b a n y a k space n below comma space a not equal to 0

a to the power of m times a to the power of n equals a to the power of m plus n end exponent. space a not equal to 0

left parenthesis a to the power of m right parenthesis to the power of n equals a to the power of m times n end exponent

 

Pertama mengubah 4 menjadi bilangan berpangkat sebagai berikut.

4 equals 2 cross times 2 equals 2 squared

Kemudian, diperoleh perhitungan:

table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator 4 to the power of n plus 1 end exponent minus 2 to the power of 2 n plus 1 end exponent over denominator 4 to the power of n end fraction end cell equals cell fraction numerator open parentheses 2 squared close parentheses to the power of n plus 1 end exponent minus 2 to the power of 2 n plus 1 end exponent over denominator open parentheses 2 squared close parentheses to the power of n end fraction end cell row blank equals cell fraction numerator 2 to the power of 2 open parentheses n plus 1 close parentheses end exponent minus 2 to the power of 2 n plus 1 end exponent over denominator 2 to the power of 2 times n end exponent end fraction end cell row blank equals cell fraction numerator 2 to the power of 2 n plus 2 end exponent minus 2 to the power of 2 n plus 1 end exponent over denominator 2 to the power of 2 n end exponent end fraction end cell row blank equals cell fraction numerator 2 to the power of 2 n end exponent times 2 squared minus 2 to the power of 2 n end exponent times 2 to the power of 1 over denominator 2 to the power of 2 n end exponent end fraction end cell row blank equals cell fraction numerator up diagonal strike 2 to the power of 2 n end exponent end strike open parentheses 2 squared minus 2 close parentheses over denominator up diagonal strike 2 to the power of 2 n end exponent end strike end fraction end cell row blank equals cell open parentheses 2 squared minus 2 close parentheses end cell row blank equals cell 4 minus 2 end cell row blank equals 2 end table  


Jadi, hasil dari fraction numerator 4 to the power of n plus 1 end exponent minus 2 to the power of 2 n plus 1 end exponent over denominator 4 to the power of n end fraction adalah table attributes columnalign right center left columnspacing 0px end attributes row blank blank 2 end table.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

1

Iklan

Iklan

Pertanyaan serupa

[ 2 ⋅ ( 2 2 ⋅ [ 2 3 ] − 1 ) − 2 ] = ...

117

5.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia