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Pertanyaan

[ 2 ⋅ ( 2 2 ⋅ [ 2 3 ] − 1 ) − 2 ] = ...

  1. 8

  2. 2

  3. 1

  4. 1 half

  5. 1 over 8

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R. Hajrianti

Master Teacher

Mahasiswa/Alumni Universitas Pendidikan Indonesia

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah A.

jawaban yang tepat adalah A.

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Pembahasan

Ingat kembali: sehingga diperoleh perhitungan: Dengan demikian, nilai dari adalah . Jadi, jawaban yang tepat adalah A.

Ingat kembali:

open parentheses a to the power of m close parentheses to the power of n equals a to the power of m times n end exponent 

a to the power of m times a to the power of n equals a to the power of m plus n end exponent

a to the power of n equals stack stack a cross times a cross times a cross times... cross times a with underbrace below with a space s e b a n y a k space n below

 

sehingga diperoleh perhitungan:

table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets 2 times open parentheses 2 squared times open square brackets 2 cubed close square brackets to the power of negative 1 end exponent close parentheses to the power of negative 2 end exponent close square brackets end cell equals cell open square brackets 2 times open parentheses 2 squared times 2 to the power of 3 times open parentheses negative 1 close parentheses end exponent close parentheses to the power of negative 2 end exponent close square brackets end cell row blank equals cell open square brackets 2 times open parentheses 2 squared times 2 to the power of negative 3 end exponent close parentheses to the power of negative 2 end exponent close square brackets end cell row blank equals cell open square brackets 2 times open parentheses 2 to the power of 2 plus open parentheses negative 3 close parentheses end exponent close parentheses to the power of negative 2 end exponent close square brackets end cell row blank equals cell open square brackets 2 times open parentheses 2 to the power of negative 1 end exponent close parentheses to the power of negative 2 end exponent close square brackets end cell row blank equals cell open square brackets 2 times 2 to the power of open parentheses negative 1 close parentheses times open parentheses negative 2 close parentheses end exponent close square brackets end cell row blank equals cell open square brackets 2 times 2 squared close square brackets end cell row blank equals cell 2 to the power of 1 plus 2 end exponent end cell row blank equals cell 2 cubed end cell row blank equals 8 end table 


Dengan demikian, nilai dari open square brackets 2 times open parentheses 2 squared times open square brackets 2 cubed close square brackets to the power of negative 1 end exponent close parentheses to the power of negative 2 end exponent close square brackets adalah table attributes columnalign right center left columnspacing 0px end attributes row blank blank 8 end table.

Jadi, jawaban yang tepat adalah A.

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