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Sebanyak 300 mL larutan HCOOH 0 , 2 M ( pH = 4 , 5 ) dicampur dengan 200 mL larutan NaOH 0 , 3 M . Berapa pH larutan setelah dicampurkan?

Sebanyak  larutan   dicampur dengan  larutan Berapa pH larutan setelahdicampurkan?

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N. Puspita

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pH larutan setelah dicampurkan adalah .

pH larutan setelah dicampurkan adalah begin mathsize 14px style 10 plus log space 4 comma 89 end style.

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Menghitung mol Menghitung mol Masukkan ke tabel MRS Karena pada tabel MRS tidak ada sisa pereaksi, campuran tersebut akan menghasilkan garam yang terhidrolisis sebagian karena pada garam terdapan ion yang terhidrolisis karena berasal dari ion asam lemah. Ionisasi HCOONa Reaksi Hidrolisis ion Menghitung konsentrasi Menghitung Menghitung Menghitung konsentrasi Menghitung Menghitung Jadi, pH larutan setelah dicampurkan adalah .

  • Menghitung mol begin mathsize 14px style H C O O H end style

Error converting from MathML to accessible text.

 

  • Menghitung mol begin mathsize 14px style Na O H end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell mol space Na O H end cell equals cell M cross times v end cell row blank equals cell 0 comma 3 space M cross times 200 space mL end cell row blank equals cell 60 space mmol end cell end table end style 
 

  • Masukkan ke tabel MRS
     


 

 

Karena pada tabel MRS tidak ada sisa pereaksi, campuran tersebut akan menghasilkan garam yang terhidrolisis sebagian karena pada garam terdapan ion H C O O to the power of minus sign yang terhidrolisis karena berasal dari ion asam lemah.

  • Ionisasi HCOONa

H C O O Na subscript space open parentheses aq close parentheses space end subscript yields H C O O to the power of minus sign subscript space open parentheses aq close parentheses space end subscript plus Na to the power of plus sign subscript space open parentheses aq close parentheses space end subscript 

  • Reaksi Hidrolisis ion H C O O to the power of minus sign

H C O O to the power of minus sign subscript open parentheses aq close parentheses space end subscript plus space H subscript 2 O subscript open parentheses l close parentheses end subscript equilibrium H C O O H subscript open parentheses aq close parentheses space end subscript and O H to the power of minus sign subscript open parentheses aq close parentheses space end subscript

  • Menghitung konsentrasi begin mathsize 14px style H C O O Na end style 

Error converting from MathML to accessible text. 
 

  • Menghitung begin mathsize 14px style open square brackets H to the power of plus sign close square brackets end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pH equals cell 4 , 5 end cell row cell left square bracket H to the power of plus right square bracket end cell equals cell 1 cross times 10 to the power of negative sign 4 , 5 end exponent end cell end table end style
 

  • Menghitung begin mathsize 14px style K subscript a end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell left square bracket H to the power of plus right square bracket end cell equals cell square root of K subscript a cross times M end root end cell row cell 1 cross times 10 to the power of negative sign 4 , 5 end exponent end cell equals cell square root of K subscript a cross times 2 cross times 10 to the power of negative sign 1 end exponent end root end cell row cell left parenthesis 1 cross times 10 to the power of negative sign 4 , 5 end exponent right parenthesis squared end cell equals cell left parenthesis square root of K subscript a cross times 2 cross times 10 to the power of negative sign 1 end exponent end root right parenthesis squared end cell row cell 1 cross times 10 to the power of negative sign 9 end exponent end cell equals cell K subscript a cross times 2 cross times 10 to the power of negative sign 1 end exponent end cell row cell K subscript a end cell equals cell fraction numerator 1 cross times 10 to the power of negative sign 9 end exponent over denominator 2 cross times 10 to the power of negative sign 1 end exponent end fraction end cell row cell K subscript a end cell equals cell 5 cross times 10 to the power of negative sign 9 end exponent end cell end table end style

 

 

 

 


 

 

 

  • Menghitung konsentrasi begin mathsize 14px style O H to the power of minus sign end style

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell left square bracket O H to the power of minus sign right square bracket end cell equals cell square root of K subscript w over K subscript a cross times open square brackets H C O O Na close square brackets cross times valensi end root end cell row cell left square bracket O H to the power of minus sign right square bracket end cell equals cell square root of fraction numerator 1 cross times 10 to the power of negative sign 14 end exponent over denominator 5 cross times 10 to the power of negative sign 9 end exponent end fraction cross times 0 , 12 cross times 1 end root end cell row cell left square bracket O H to the power of minus sign right square bracket end cell equals cell square root of 24 cross times 10 to the power of negative sign 8 end exponent end root end cell row blank equals cell 4 , 89 cross times 10 to the power of negative sign 4 end exponent end cell end table end style

 

 

 

 

 

  • Menghitung undefined 

Error converting from MathML to accessible text.


 

  • Menghitung begin mathsize 14px style pH end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pH equals cell 14 minus sign pOH end cell row blank equals cell 14 minus sign open parentheses 4 minus sign log space 4 , 89 close parentheses end cell row blank equals cell 10 plus log space 4 , 89 end cell end table end style

 



Jadi, pH larutan setelah dicampurkan adalah begin mathsize 14px style 10 plus log space 4 comma 89 end style.

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