Roboguru

Sebanyak direaksikan dengan menurut reaksi (belum setara) berikut. Konsentrasi setelah reaksi adalah ........

Sebanyak 5 space m l space L i O H space 0 comma 1 space M direaksikan dengan 5 space m l space H subscript 2 S O subscript 4 space 0 comma 1 space M menurut reaksi (belum setara) berikut.

L i O H left parenthesis a q right parenthesis plus H subscript 2 S O subscript 4 left parenthesis a q right parenthesis rightwards arrow L i subscript 2 S O subscript 4 left parenthesis a q right parenthesis plus H subscript 2 O left parenthesis l right parenthesis

Konsentrasi H subscript 2 S O subscript 4 setelah reaksi adalah ........

  1. 0,025 M

  2. 0,075 M

  3. 0,100 M

  4. 0,125 M

  5. 0,250 M

Jawaban:

M o l space L i O H equals M cross times V equals 0 comma 1 space M cross times 5 space m L equals 0 comma 5 space m m o l  M o l space H subscript 2 S O subscript 4 equals 0 comma 1 space M cross times 5 space m L equals 0 comma 5 space m m o l  M a s u k a n space d a l a m space p e r s a m a a n space r e a k s i space s e t a r a space colon  space space space space space space space space space space space space space space space space space 2 L i O H space space space space space space plus space space space H subscript 2 S O subscript 4 space space space space space space space rightwards arrow space space space space L i subscript 2 S O subscript 4 space space space space space space space plus space space 2 H subscript 2 O  M u l a space space space space space space 0 comma 5 space m m o l space space space space space space space space 0 comma 5 space m m o l  R e a k s i space space 0 comma 5 space m m o l space space space space space space space space 0 comma 25 space m m o l space space space space space space space space space 0 comma 25 space m m o l space space space space space space space space 0 comma 5 space m m o l space space space  S i s a space space space space space space space space 0 space space space space space space space space space space space space space space space space space space space space space 0 comma 25 space m m o l space space space space space space space space space 0 comma 25 space m m o l space space space space space space space space 0 comma 5 space m m o l  left square bracket H subscript 2 S O subscript 4 right square bracket space s i s a equals fraction numerator m o l space s i s a over denominator v o l u m e space t o t a l end fraction equals fraction numerator 0 comma 25 space m m o l over denominator 10 space m L end fraction equals 0 comma 025 space M

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