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Pertanyaan

Sebanyak 50 mL larutan CH3COOH 0,2 M bereaksi dengan 50 mL larutan NaOH 0,2 M sesuai dengan reaksi:
CH3COOH (aq) + NaOH (aq) → CH3COONa (aq) + H2O ()
Jika Ka CH3COOH = 10-5 , maka pH campuran yang terjadi adalah ….

  1. 2-log2

  2. 5+log 1

  3. 5+ log2

  4. 9+log 1

  5. 9 + log 2

N. Puji

Master Teacher

Mahasiswa/Alumni Universitas Sebelas Maret

Jawaban terverifikasi

Pembahasan

begin mathsize 14px style Mol space CH subscript 3 COOH space equals space straight M space straight x space straight V space equals space 0 comma 2 straight M space straight x space 50 space mL space equals space 10 space mmol space  Mol space NaOH space equals space straight M space straight x space straight V space equals space 0 comma 2 straight M space straight x space 50 space mL space equals space 10 space mmol  space Persamaan space reaksi space colon  space space space space space space space space space space space space space space space space space space space space space space space space space space CH subscript 3 COOH left parenthesis aq right parenthesis space plus space NaOH left parenthesis aq right parenthesis space rightwards arrow space CH subscript 3 COONa left parenthesis aq right parenthesis space plus space straight H subscript 2 straight O left parenthesis straight l right parenthesis space  Mula minus mula space colon space space space space space space space space space space 10 space mmol space space space space space space space space space space 10 space mmol space space space space space space space space space space space space space space space space space minus space space space space space space space space space space space space space space space space space space space space space space space minus space  Reaksi space space space space space space space space space colon space space space space space space minus space 10 space mmol space space space space space space space space minus space 10 space mmol space space space space space space space space space space plus space 10 space mmol space space space space space plus space space 10 space mmol  stack Sisa space space space space space space space space space space space space space space colon space space space space space space space space space space space space minus space space space space space space space space space space space space space space space space space space space space space space space minus space space space space space space space space space space space space space space space space space space space space space 10 space mmol space space space space space space space space space space space space space 10 space mmol with bar on top  Karena space yang space tersisa space hanya space garam space dan space air comma space maka space menggunakan space rumus space hidrolisis. space space space  left square bracket straight G right square bracket space equals fraction numerator m o l over denominator V end fraction space space equals fraction numerator 10 space m m o l over denominator 100 space m L end fraction space space equals space 10 to the power of negative 1 end exponent space straight M space space  OH minus space equals space square root of fraction numerator K w over denominator K a end fraction left square bracket G right square bracket end root space space equals square root of 10 to the power of negative 14 end exponent over 10 to the power of negative 5 end exponent left square bracket 10 to the power of negative 1 end exponent right square bracket end root space equals space 10 to the power of negative 5 end exponent space  pOH space equals space minus space log space left square bracket OH minus right square bracket space space  space space space space space space space space equals space minus space log space 10 to the power of negative 5 end exponent space space equals space 5 space  pH space space space equals space 14 space – space pOH space equals space 14 space – space 5 space equals space 9 space space space atau space 9 space plus space log space 1 space left parenthesis karena space log space 1 space equals space 0 right parenthesis end style

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