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Sebanyak 50 mL larutan Ca(NO 3 ) 2 10 -2 M dicampurkan dengan 50 mL larutan Na 2 C O 3 10 -2 M dengan reaksi: C a ( N O 3 ​ ) 2 ​ ( a q ) + N a 2 ​ C O 3 ​ ( a q ) → C a C O 3 ​ ( s ) + 2 N a N O 3 ​ ( a q ) Jika Ksp CaCO 3 = 9x10 -9 Massa yang mengendap sebanyak... (Ar Ca = 40 ; C = 12 ; O = 16 ; Na = 23 ; N = 14)

Sebanyak 50 mL larutan Ca(NO3)2 10-2 M dicampurkan dengan 50 mL larutan Na2CO3  10-2 M dengan reaksi:

Jika Ksp CaCO3 = 9x10-9 Massa yang mengendap sebanyak...

(Ar Ca = 40 ; C = 12 ; O = 16 ; Na = 23 ; N = 14)

  1. 100 gram

  2. 0,100 gram

  3. 0,050 gram

  4. 0,025 gram

  5. 0,0025 gram

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D. Ayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

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endapan CaCO 3 yang terbentuk? Mmol CaCO 3 yang terbentuk adalah 0,5 mmol. gram CaCO 3 = 5 x 10 - 4 mol x 100 = 0,05 gram

space space space space space space C a left parenthesis N O subscript 3 right parenthesis subscript 2 left parenthesis a q right parenthesis space space space space space space space space space space plus space space space space space space N a subscript 2 C O subscript 3 left parenthesis a q right parenthesis space space space space space rightwards arrow space space space space C a C O subscript 3 left parenthesis s right parenthesis space space space plus space space space space 2 N a N O subscript 3  M equals 10 to the power of negative 2 end exponent M cross times 50 m L space space space space space space space space space space space space space space space space space 10 to the power of negative 2 end exponent M cross times 50 m L  space space space space equals space 0 comma 5 space m m o l space space space space space space space space space space space space space space space space space space space space space space space space space equals space 0 comma 5 space m m o l space space space space space space space space space space space space space space space space space space minus space space space space space space space space space space space space space space space space space space space space space space space space space minus  fraction numerator R equals space 0 comma 5 space m m o l space space space space space space space space space space space space space space space space space space space space space space space space space space space 0 comma 5 space m m o l space space space space space space space space space space space space space space space space space space 0 comma 5 space m m o l space space space space space space space space space space 0 comma 5 space m m o l over denominator S equals space space space space minus space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space minus space space space space space space space space space space space space space space space space space space space space space space space 0 comma 5 space m m o l space space space space space space space space space space space 0 comma 5 space m m o l end fraction

endapan CaCO3 yang terbentuk?

Mmol CaCO3 yang terbentuk adalah 0,5 mmol.

M o l space C a C O subscript 3 space equals space fraction numerator g r a m space C a C O subscript 3 over denominator M r end fraction  5 cross times 10 to the power of negative 4 end exponent space m o l space equals space fraction numerator g r a m space C a C O subscript 3 over denominator 100 end fraction

gram CaCO3 = 5 x 10-4mol x 100  = 0,05 gram

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