Pertanyaan

Sebanyak 3,7 gram Ca ( OH ) 2 ​ dilarutkan dalam 5 L air. Larutan tersebut memiliki pH sebesar .... ( A r ​ Ca = 40, O = 16, dan H = 1 )

Sebanyak 3,7 gram  dilarutkan dalam 5 L air. Larutan tersebut memiliki pH sebesar ....
( Ca = 40, O = 16, dan H = 1 )

  1. begin mathsize 14px style 2 minus sign log space 2 end style  

  2. begin mathsize 14px style 2 plus log space 2 end style  

  3. begin mathsize 14px style 12 plus log space 1 end style  

  4. begin mathsize 14px style 12 minus sign log space 2 end style 

  5. begin mathsize 14px style 12 plus log space 2 end style 

S. Susanti

Master Teacher

Mahasiswa/Alumni Universitas Jayabaya

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah E.

jawaban yang benar adalah E.

Pembahasan

Pembahasan

Diketahui: Berikut penyelesaian dalam soal: Mencari mol Mencari konsentrasi Mencari Mencari pH Jadi, jawaban yang benar adalah E.

Diketahui:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell V space air space end cell equals cell space 5 space L end cell row cell m space Ca open parentheses O H close parentheses subscript 2 end cell equals cell 3 comma 7 space g end cell row cell Mr space Ca open parentheses O H close parentheses subscript 2 end cell equals cell left square bracket Ar space Ca plus 2 left parenthesis Ar space O right parenthesis plus 2 left parenthesis Ar space H right parenthesis right square bracket g forward slash mol end cell row blank equals cell left square bracket 40 plus 2 left parenthesis 16 right parenthesis plus 2 left parenthesis 1 right parenthesis right square bracket g forward slash mol end cell row blank equals cell left parenthesis 40 plus 32 plus 2 right parenthesis space g forward slash mol end cell row blank equals cell 74 space g forward slash mol end cell end table end style

Berikut penyelesaian dalam soal:

  1. Mencari mol begin mathsize 14px style Ca open parentheses O H close parentheses subscript 2 end style

    begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row n equals cell m over Mr end cell row blank equals cell fraction numerator 3 comma 7 space g over denominator 74 space g forward slash mol end fraction end cell row blank equals cell 0 comma 05 space mol end cell end table end style
     
  2. Mencari konsentrasi begin mathsize 14px style Ca open parentheses O H close parentheses subscript 2 end style

    begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row M equals cell n over V end cell row blank equals cell fraction numerator 0 comma 05 space mol over denominator 5 space L end fraction end cell row blank equals cell 10 to the power of negative sign 2 end exponent space M end cell end table end style
     
  3. Mencari begin mathsize 14px style open square brackets O H to the power of minus sign close square brackets end style

    begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell M cross times valensi space basa end cell row blank equals cell 10 to the power of negative sign 2 space end exponent M cross times 2 end cell row blank equals cell 2 cross times 10 to the power of negative sign 2 end exponent space M end cell end table end style
     
  4. Mencari pH begin mathsize 14px style Ca open parentheses O H close parentheses subscript 2 end style

    begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pOH equals cell negative sign log space open square brackets O H to the power of minus sign close square brackets end cell row blank equals cell negative sign log space 2 cross times 10 to the power of negative sign 2 end exponent end cell row blank equals cell 2 minus sign log space 2 end cell end table end style 

    begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pH equals cell 14 minus sign pOH end cell row blank equals cell 14 minus sign left parenthesis 2 minus sign log space 2 right parenthesis end cell row blank equals cell 12 plus log space 2 end cell end table end style

Jadi, jawaban yang benar adalah E.

881

4.3 (18 rating)

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