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Sebanyak 100 ml larutan KF mempunyai pH sebesar 8. Jika K a ​ HF = 7 , 2 × 1 0 − 4 ,konsentrasi larutan KF sebesar ....

Sebanyak 100 ml larutan KF mempunyai pH sebesar 8. Jika , konsentrasi larutan KF sebesar ....

  1. 0,0 18 M

  2. 0,036 M

  3. 0,072 M

  4. 0,144 M

  5. 0;720 M

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Jawaban terverifikasi

Jawaban

jawaban yang benar adalah C.

jawaban yang benar adalah C.

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Pembahasan
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KF adalah garam yang akan mengalami hidrolisis parsial di dalam air dan menghasilkan ion , sesuai reaksi berikut. Untuk menentukan [HF], di hitung nilai melalui pH larutan KF. Jadi, jawaban yang benar adalah C.

KF adalah garam yang akan mengalami hidrolisis parsial di dalam air dan menghasilkan ion begin mathsize 14px style O H to the power of minus sign end style, sesuai reaksi berikut.

begin mathsize 14px style space space space space space space space space space space space K F yields K to the power of plus sign and F to the power of minus sign F to the power of minus sign and H subscript 2 O yields H F and O H to the power of minus sign end style 

Untuk menentukan [HF], di hitung nilai begin mathsize 14px style open square brackets F to the power of minus sign close square brackets end style melalui pH larutan KF.

begin mathsize 14px style space space space space space space space space space space pH equals 8 14 minus pOH equals 8 space space space space space space space pOH equals 14 minus 8 space space space space space space space pOH equals 6 left square bracket OH to the power of minus right square bracket equals 10 to the power of negative 6 end exponent  space space left square bracket OH to the power of minus right square bracket equals square root of straight K subscript straight w over straight K subscript straight a space cross times space left square bracket straight F to the power of minus right square bracket end root left parenthesis 10 to the power of negative 6 end exponent right parenthesis squared equals open parentheses square root of fraction numerator 10 to the power of negative 14 end exponent over denominator 7 comma 2 space cross times space 10 to the power of negative 4 end exponent end fraction space cross times space left square bracket straight F to the power of minus right square bracket end root close parentheses squared space space 10 to the power of negative 12 end exponent equals fraction numerator 10 to the power of negative 14 end exponent over denominator 7 comma 2 space cross times space 10 to the power of negative 4 end exponent end fraction space cross times space left square bracket straight F to the power of minus right square bracket space space space space space left square bracket straight F to the power of minus right square bracket equals 7 comma 2 space cross times space 10 to the power of negative 2 end exponent space space space space space left square bracket straight F to the power of minus right square bracket equals 0 comma 072 space straight M end style   

 

begin mathsize 14px style open square brackets K F close square brackets equals open square brackets F to the power of minus sign close square brackets equals 0 comma 072 space M end style

Jadi, jawaban yang benar adalah C.

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