Iklan

Iklan

Pertanyaan

Larutan NaOH dengan volume 100 mL mempunyai pH sebesar 12 + log 6 dicampurkan ke dalam 400 mL larutan CH 3 ​ COOH dengan pH sebesar 3,5 - log 3. Jika harga K a ​ CH 3 ​ COOH = 6 , 0 × 1 0 − 5 , hitung pH campuran yang terbentuk!

Larutan  dengan volume 100 mL mempunyai pH sebesar 12 + log 6 dicampurkan ke dalam 400 mL larutan  dengan pH sebesar 3,5 - log 3. Jika harga  = , hitung pH campuran yang terbentuk!

Iklan

D. Vitama

Master Teacher

Mahasiswa/Alumni Universitas Islam Negeri Sunan Kalijaga

Jawaban terverifikasi

Jawaban

pH campuran tersebut adalah 9 + log 1,4 atau 9,15.

pH campuran tersebut adalah 9 + log 1,4 atau 9,15.

Iklan

Pembahasan

Menentukan konsentrasi NaOH: Menentukan konsentrasi C 6 H 5 COOH: Menentukan mol sisa zat: pH campuran Jadi, pH campuran tersebut adalah 9 + log 1,4 atau 9,15.

Menentukan konsentrasi NaOH:

pOH equals 14 minus sign pH pOH equals 14 minus sign left parenthesis 12 plus log space 6 right parenthesis pOH equals 2 minus sign log space 6  pOH equals minus sign log space open square brackets O H to the power of minus sign close square brackets 2 minus sign log space 6 equals minus sign log space open square brackets O H to the power of minus sign close square brackets open square brackets O H to the power of minus sign close square brackets equals 6 cross times 10 to the power of negative sign 2 end exponent  open square brackets O H to the power of minus sign close square brackets double bond b cross times M 6 cross times 10 to the power of negative sign 2 end exponent equals 1 cross times M M space Na O H equals 0 comma 06 space M 

Menentukan konsentrasi C6H5COOH:

pH equals minus sign log space open square brackets H to the power of plus sign close square brackets 3 comma 5 minus sign log space 3 equals minus sign log space open square brackets H to the power of plus sign close square brackets open square brackets H to the power of plus sign close square brackets equals 3 cross times 10 to the power of negative sign 3 comma 5 end exponent  open square brackets H to the power of plus sign close square brackets equals square root of K subscript a cross times M end root 9 cross times 10 to the power of negative sign 7 end exponent equals 6 cross times 10 to the power of negative sign 5 end exponent cross times M M space C subscript 6 H subscript 5 C O O H equals 0 comma 015 space M  

Menentukan mol sisa zat:
 

 
 

pH campuran
 

open square brackets O H to the power of minus sign close square brackets equals square root of Kw over Ka cross times open square brackets G close square brackets end root open square brackets O H to the power of minus sign close square brackets equals square root of fraction numerator 10 to the power of negative sign 14 end exponent over denominator 6 cross times 10 to the power of negative sign 5 end exponent end fraction cross times 6 over 500 end root open square brackets O H to the power of minus sign close square brackets equals square root of 2 cross times 10 to the power of negative sign 10 end exponent end root open square brackets O H to the power of minus sign close square brackets equals 1 comma 4 cross times 10 to the power of negative sign 5 end exponent  pOH equals minus sign log space open square brackets O H to the power of minus sign close square brackets pOH equals minus sign log space 1 comma 4 cross times 10 to the power of negative sign 5 end exponent pOH equals 5 minus sign log space 1 comma 4  pH equals 14 minus sign pOH pH equals 14 minus sign left parenthesis 5 minus sign log space 1 comma 4 right parenthesis pH equals 9 plus log space 1 comma 4 almost equal to 9 comma 15 
 

Jadi, pH campuran tersebut adalah 9 + log 1,4 atau 9,15.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

4

Iklan

Iklan

Pertanyaan serupa

Tetapan hidrolisis NaBrO sebesar .... ( K a ​ HBrO = 2 × 1 0 − 5 )

23

4.2

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia