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Pertanyaan

Larutan NaOH dengan volume 100 mL mempunyai pH sebesar 12 + log 6 dicampurkan ke dalam 400 mL larutan CH 3 ​ COOH dengan pH sebesar 3,5 - log 3. Jika harga K a ​ CH 3 ​ COOH = 6 , 0 × 1 0 − 5 , hitung pH campuran yang terbentuk!

Larutan  dengan volume 100 mL mempunyai pH sebesar 12 + log 6 dicampurkan ke dalam 400 mL larutan  dengan pH sebesar 3,5 - log 3. Jika harga  = , hitung pH campuran yang terbentuk!

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D. Vitama

Master Teacher

Mahasiswa/Alumni Universitas Islam Negeri Sunan Kalijaga

Jawaban terverifikasi

Jawaban

pH campuran tersebut adalah 9 + log 1,4 atau 9,15.

pH campuran tersebut adalah 9 + log 1,4 atau 9,15.

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Pembahasan

Menentukan konsentrasi NaOH: Menentukan konsentrasi C 6 H 5 COOH: Menentukan mol sisa zat: pH campuran Jadi, pH campuran tersebut adalah 9 + log 1,4 atau 9,15.

Menentukan konsentrasi NaOH:

pOH equals 14 minus sign pH pOH equals 14 minus sign left parenthesis 12 plus log space 6 right parenthesis pOH equals 2 minus sign log space 6  pOH equals minus sign log space open square brackets O H to the power of minus sign close square brackets 2 minus sign log space 6 equals minus sign log space open square brackets O H to the power of minus sign close square brackets open square brackets O H to the power of minus sign close square brackets equals 6 cross times 10 to the power of negative sign 2 end exponent  open square brackets O H to the power of minus sign close square brackets double bond b cross times M 6 cross times 10 to the power of negative sign 2 end exponent equals 1 cross times M M space Na O H equals 0 comma 06 space M 

Menentukan konsentrasi C6H5COOH:

pH equals minus sign log space open square brackets H to the power of plus sign close square brackets 3 comma 5 minus sign log space 3 equals minus sign log space open square brackets H to the power of plus sign close square brackets open square brackets H to the power of plus sign close square brackets equals 3 cross times 10 to the power of negative sign 3 comma 5 end exponent  open square brackets H to the power of plus sign close square brackets equals square root of K subscript a cross times M end root 9 cross times 10 to the power of negative sign 7 end exponent equals 6 cross times 10 to the power of negative sign 5 end exponent cross times M M space C subscript 6 H subscript 5 C O O H equals 0 comma 015 space M  

Menentukan mol sisa zat:
 

 
 

pH campuran
 

open square brackets O H to the power of minus sign close square brackets equals square root of Kw over Ka cross times open square brackets G close square brackets end root open square brackets O H to the power of minus sign close square brackets equals square root of fraction numerator 10 to the power of negative sign 14 end exponent over denominator 6 cross times 10 to the power of negative sign 5 end exponent end fraction cross times 6 over 500 end root open square brackets O H to the power of minus sign close square brackets equals square root of 2 cross times 10 to the power of negative sign 10 end exponent end root open square brackets O H to the power of minus sign close square brackets equals 1 comma 4 cross times 10 to the power of negative sign 5 end exponent  pOH equals minus sign log space open square brackets O H to the power of minus sign close square brackets pOH equals minus sign log space 1 comma 4 cross times 10 to the power of negative sign 5 end exponent pOH equals 5 minus sign log space 1 comma 4  pH equals 14 minus sign pOH pH equals 14 minus sign left parenthesis 5 minus sign log space 1 comma 4 right parenthesis pH equals 9 plus log space 1 comma 4 almost equal to 9 comma 15 
 

Jadi, pH campuran tersebut adalah 9 + log 1,4 atau 9,15.

Latihan Bab

Konsep Kilat

Pendahuluan Hidrolisis Garam

Hidrolisis Parsial Garam Asam

Hidrolisis Parsial Garam Basa

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