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Sebanyak 10 mol gas ideal monoatomik menjalani siklus ABCA (AB lurus) seperti pada gambar. Jumlah kalor yang diserap gas selama proses AB adalah ....

 

Sebanyak 10 mol gas ideal monoatomik menjalani siklus ABCA (AB lurus) seperti pada gambar.

begin mathsize 14px style p subscript A equals 2 over 3 p subscript B equals 8 comma 3 cross times 10 to the power of 5 space straight N space straight m to the power of negative 2 end exponent V subscript A equals 1 half V subscript B comma space T subscript A equals 10 cubed space straight K R equals 8 comma 3 space straight J space mol to the power of negative 1 end exponent space straight K to the power of negative 1 end exponent end style 

Jumlah kalor yang diserap gas selama proses AB adalah .... 

  1. begin mathsize 14px style 5 comma 2 cross times 10 to the power of 5 space straight J end style 

  2. begin mathsize 14px style 4 comma 7 cross times 10 to the power of 5 space straight J end style 

  3. begin mathsize 14px style 3 comma 5 cross times 10 to the power of 5 space straight J end style 

  4. begin mathsize 14px style 2 comma 1 cross times 10 to the power of 5 space straight J end style 

  5. begin mathsize 14px style 1 comma 2 cross times 10 to the power of 5 space straight J end style 

Jawaban:

Hitung volume di titik A:

begin mathsize 14px style p subscript A V subscript A equals n R T subscript A V subscript A equals fraction numerator 10 cross times 8 comma 3 cross times 1000 over denominator 8 comma 3 cross times 10 to the power of 5 end fraction V subscript A equals 0 comma 1 space straight m cubed. end style 

Hitung suhu pada titik B:

begin mathsize 14px style fraction numerator p subscript A V subscript A over denominator T subscript A end fraction equals fraction numerator p subscript B V subscript B over denominator T subscript B end fraction fraction numerator open parentheses begin display style 2 over 3 end style p subscript B close parentheses open parentheses begin display style 1 half end style V subscript B close parentheses over denominator 1000 end fraction equals fraction numerator p subscript B V subscript B over denominator T subscript B end fraction T subscript B equals 3000 space straight K. end style 

Hitung perubahan energi dalam gas pada proses AB:

begin mathsize 14px style capital delta U subscript A B end subscript equals 3 over 2 n R capital delta T capital delta U subscript A B end subscript equals 3 over 2 cross times 10 cross times 8 comma 3 cross times open parentheses 3000 minus 1000 close parentheses capital delta U subscript A B end subscript equals 2 comma 49 cross times 10 to the power of 5 space straight J. end style 

Hitung usaha gas pada proses AB:

begin mathsize 14px style W subscript A B end subscript equals l u a s space t r a p e s i u m W subscript A B end subscript equals fraction numerator open parentheses p subscript A plus p subscript B close parentheses over denominator 2 end fraction cross times open parentheses V subscript B minus V subscript A close parentheses W subscript A B end subscript equals fraction numerator open parentheses begin display style 5 over 3 end style p subscript B close parentheses over denominator 2 end fraction cross times open parentheses 2 V subscript A minus V subscript A close parentheses W subscript A B end subscript equals 5 over 6 cross times p subscript B cross times V subscript A W subscript A B end subscript equals 5 over 6 cross times 12 comma 45 cross times 10 to the power of 5 cross times 0 comma 1 W subscript A B end subscript equals 1 comma 0375 cross times 10 to the power of 5 space straight J. end style 

Sehingga, berdasarkan hukum I Termodinamika diperoleh kalor yang diserap gas selama proses AB yaitu:

begin mathsize 14px style Q subscript A B end subscript equals W subscript A B end subscript plus capital delta U subscript A B end subscript Q subscript A B end subscript equals left parenthesis 1 comma 0375 plus 2 comma 49 right parenthesis cross times 10 to the power of 5 Q subscript A B end subscript equals 3 comma 5 cross times 10 to the power of 5 space straight J. end style 

Oleh karena itu, jawaban yang benar adalah C. 

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