Roboguru

Reaksi fase gas berikut berlangsung pada suhu 600 ...

Reaksi fase gas berikut berlangsung pada suhu 600 K:


begin mathsize 14px style C H subscript 3 N subscript 2 C H subscript 3 space rightwards arrow space C H subscript 3 C H subscript 3 space plus space N subscript 2 end style 


Tekanan parsial reaktan sebagai fungsi waktu ditunjukkan dengan data sebagai berikut:


 


Tentukan orde dan tetapan laju reaksi tersebut!

Jawaban:

  


begin mathsize 14px style v subscript 1 equals minus sign fraction numerator increment P over denominator increment t end fraction equals minus sign fraction numerator P subscript 1 bond P subscript 0 over denominator t subscript 1 bond t subscript 0 end fraction equals minus sign fraction numerator left parenthesis 5 comma 72 minus sign 8 comma 20 right parenthesis. space 10 to the power of negative sign 2 end exponent over denominator 1000 minus sign 0 end fraction equals 2 comma 48.10 to the power of negative sign 5 end exponent space begin inline style bevelled mmHg over s end style end style 

begin mathsize 14px style v subscript 2 equals minus sign fraction numerator increment P over denominator increment t end fraction equals minus sign fraction numerator P subscript 2 bond P subscript 1 over denominator t subscript 2 bond t subscript 1 end fraction equals minus sign fraction numerator left parenthesis 3 comma 99 minus sign 5 comma 72 right parenthesis. space 10 to the power of negative sign 2 end exponent over denominator 2000 minus sign 1000 end fraction equals 1 comma 73.10 to the power of negative sign 5 end exponent space begin inline style bevelled mmHg over s end style end style 


Menentukan orde reaksi (x)


begin mathsize 14px style v subscript 1 over v subscript 2 equals fraction numerator italic k. P subscript 1 to the power of italic x over denominator italic k. P subscript 2 to the power of italic x end fraction fraction numerator 2 comma 48.10 to the power of negative sign 5 end exponent over denominator 1 comma 73.10 to the power of negative sign 5 end exponent end fraction equals fraction numerator up diagonal strike italic k. left parenthesis 5 comma 72.10 to the power of negative sign 2 end exponent right parenthesis to the power of italic x over denominator up diagonal strike italic k. left parenthesis 3 comma 99.10 to the power of negative sign 2 end exponent right parenthesis to the power of italic x end fraction 1 comma 43 equals left parenthesis 1 comma 43 right parenthesis to the power of x x equals 1 end style 


Menentukan tetapan laju reaksi (k)


begin mathsize 14px style v subscript 1 equals italic k point P subscript 1 2 comma 48.10 to the power of negative sign 5 end exponent equals italic k.5 comma 72.10 to the power of negative sign 2 end exponent fraction numerator 2 comma 48.10 to the power of negative sign 5 end exponent over denominator 5 comma 72.10 to the power of negative sign 2 end exponent end fraction equals italic k italic k equals 0 comma 43.10 to the power of negative sign 3 end exponent equals 4 comma 3.10 to the power of negative sign 4 end exponent space begin inline style bevelled mmHg over s end style end style 


Jadi, orde reaksinya adalah 1 dan tetapan laju reaksinya adalah begin mathsize 14px style bold 4 bold comma bold 3 bold. bold 10 to the power of bold minus sign bold 4 end exponent bold space begin inline style bevelled bold mmHg over italic s end style end style.space  

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