Reaksi berikut merupakan reaksi orde 1 terhadap H2​O2​   2H2​O2​(aq)→2H2​O(l)+O2​(g) Jika laju awal penguraian H2​O2​ adalah 5,6×10−5 M/s, maka laju reaksi pada saat [H2​O2​] tersisa 25% adalah ...

Pertanyaan

Reaksi berikut merupakan reaksi orde 1 terhadap H subscript 2 O subscript 2
 

2 H subscript 2 O subscript 2 left parenthesis italic a italic q right parenthesis yields 2 H subscript 2 O open parentheses italic l close parentheses and O subscript 2 open parentheses italic g close parentheses


Jika laju awal penguraian H subscript 2 O subscript 2 adalah 5 comma 6 cross times 10 to the power of negative sign 5 space end exponent M forward slash s, maka laju reaksi pada saat open square brackets H subscript 2 O subscript 2 close square brackets tersisa 25 percent sign adalah ...space

  1. 1 comma 4 cross times 10 to the power of negative sign 5 end exponent

  2. 1 comma 8 cross times 10 to the power of negative sign 5 end exponent

  3. 2 comma 7 cross times 10 to the power of negative sign 5 end exponent

  4. 5 comma 4 cross times 10 to the power of negative sign 5 end exponent

  5. 7 comma 2 cross times 10 to the power of negative sign 5 end exponent

B. Rohmawati

Master Teacher

Mahasiswa/Alumni Universitas Negeri Semarang

Jawaban terverifikasi

Jawaban

laju reaksi pada saat H subscript 2 O subscript 2 tersisa 25 percent sign adalah 1 comma 4 cross times 10 to the power of negative sign 5 end exponent space M forward slash s.

Pembahasan

Jawaban yang benar adalah opsi A.

Persamaan laju reaksi v double bond k open square brackets H subscript 2 O subscript 2 close square brackets

v subscript 1 equals 5 comma 6 cross times 10 to the power of negative sign 5 end exponent space M forward slash s saat open square brackets H subscript 2 O subscript 2 close square brackets equals 100 percent sign

table attributes columnalign right center left columnspacing 0px end attributes row cell v subscript 1 over v subscript 2 end cell equals cell fraction numerator k open square brackets H subscript 2 O subscript 2 close square brackets subscript 1 over denominator k open square brackets H subscript 2 O subscript 2 close square brackets subscript 2 end fraction end cell row cell fraction numerator 5 comma 6 cross times 10 to the power of negative sign 5 end exponent over denominator v subscript 2 end fraction end cell equals cell fraction numerator k left square bracket 100 percent sign right square bracket over denominator k left square bracket 25 percent sign right square bracket end fraction end cell row cell v subscript 2 end cell equals cell fraction numerator 5 comma 6 cross times 10 to the power of negative sign 5 end exponent over denominator 4 end fraction end cell row cell v subscript 2 end cell equals cell 1 comma 4 cross times 10 to the power of negative sign 5 end exponent space M forward slash s end cell end table 

Jadi, laju reaksi pada saat H subscript 2 O subscript 2 tersisa 25 percent sign adalah 1 comma 4 cross times 10 to the power of negative sign 5 end exponent space M forward slash s.

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