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pH larutan asam etanoat 0,3 M () adalah ...

Pertanyaan

pH larutan asam etanoat 0,3 M (begin mathsize 14px style Ka equals 2 x 10 to the power of negative sign 5 end exponent end style) adalah ...

  1. 3 - log 2

  2. 1 - log 2

  3. 4 - log 4

  4. 2 - log 2

  5. 5 - log 2

Pembahasan Soal:

menentukan begin mathsize 14px style open square brackets H to the power of plus sign close square brackets end style

begin mathsize 14px style open square brackets H to the power of plus sign close square brackets space equals space square root of Ka space x space M end root open square brackets H to the power of plus sign close square brackets space equals space square root of 2 x 10 to the power of negative sign 5 end exponent space. space 3 x 10 to the power of negative sign 1 end exponent end root open square brackets H to the power of plus sign close square brackets space equals space square root of 6 space x space 10 to the power of negative sign 6 end exponent end root open square brackets H to the power of plus sign close square brackets space equals left parenthesis square root of 6 right parenthesis x space 10 to the power of negative sign 3 end exponent space end style

menentukan pH

begin mathsize 14px style pH equals minus sign log space open square brackets H to the power of plus sign close square brackets pH equals minus sign space log space square root of 6 space end root space x space 10 to the power of negative sign 3 end exponent pH equals 3 space minus sign space log space square root of 6 space end root pH equals 3 space minus sign space log space 2 comma 45 end style

Jadi, jawaban yang benar adalah A.
 

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 04 April 2021

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