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Pertidaksamaan 2 + 5 x − 3 x 2 ≤ 2 − 5 x − x 2 ,mempunyai penyelesaian....

Pertidaksamaan , mempunyai penyelesaian....

  1. ​​​​​​begin mathsize 14px style x less than 0 space end styleatau begin mathsize 14px style x greater than 5 end style

  2. begin mathsize 14px style x less or equal than 0 end style atau 5

  3. 0 less or equal than x less or equal than 5

  4. begin mathsize 14px style x less than 2 end style atau begin mathsize 14px style x greater or equal than negative 5 end style

  5. begin mathsize 14px style negative 2 less than x less or equal than 0 end style atau begin mathsize 14px style 4 less than x less or equal than 5 end style

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M. Mariyam

Master Teacher

Mahasiswa/Alumni Institut Pertanian Bogor

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himpunan penyelesaiannya adalah

himpunan penyelesaiannya adalah left curly bracket 0 less or equal than x less or equal than 5 right curly bracket

Pembahasan

Jadi, himpunan penyelesaiannya adalah

size 14px 2 size 14px plus size 14px 5 size 14px x size 14px minus size 14px 3 size 14px x to the power of size 14px 2 size 14px less or equal than size 14px 2 size 14px minus size 14px 5 size 14px x size 14px minus size 14px x to the power of size 14px 2 size 14px 2 size 14px plus size 14px 5 size 14px x size 14px minus size 14px 3 size 14px x to the power of size 14px 2 size 14px minus size 14px 2 size 14px plus size 14px 5 size 14px x size 14px plus size 14px x to the power of size 14px 2 size 14px less or equal than size 14px 0 size 14px minus size 14px 2 size 14px x to the power of size 14px 2 size 14px plus size 14px 10 size 14px x size 14px less or equal than size 14px 0 size 14px space size 14px space size 14px left parenthesis size 14px k size 14px e size 14px d size 14px u size 14px a size 14px space size 14px r size 14px u size 14px a size 14px s size 14px space size 14px d size 14px i size 14px b size 14px a size 14px g size 14px i size 14px space size 14px minus size 14px 2 size 14px right parenthesis size 14px x to the power of size 14px 2 size 14px minus size 14px 5 size 14px x size 14px greater or equal than size 14px 0 size 14px x size 14px left parenthesis size 14px x size 14px minus size 14px 5 size 14px right parenthesis size 14px greater or equal than size 14px 0 x equals 0 space d a n space x equals 5

    Jadi, himpunan penyelesaiannya adalah left curly bracket 0 less or equal than x less or equal than 5 right curly bracket

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Himpunan penyelesaian dari pertidaksamaan untuk x 2 ≤ 2 x + 3 adalah . . .

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