Pertanyaan

Persamaan lingkaran x 2 + y 2 − 2 x − 6 y = 0 setelah dilatasi dengan pusat (2,1) dan faktor skala 3 adalah…

Persamaan lingkaran $x^{2} + y^{2} - 2 x - 6 y = 0$ setelah dilatasi dengan pusat (2,1) dan faktor skala 3 adalah…

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Habis dalam

Klaim

Y. Laksmi

Master Teacher

Mahasiswa/Alumni Universitas Negeri Semarang

Jawaban terverifikasi

Pembahasan

Pusat Persamaan Lingkaran Substitusikan ke persamaan , didapat

Pusat

Persamaan Lingkaran

$x apostrophe equals 3 x minus 4 space space space space space space space y apostrophe equals 3 y minus 2 x equals fraction numerator x apostrophe plus 4 over denominator 3 end fraction space space space space space space space y equals fraction numerator y apostrophe plus 2 over denominator 3 end fraction$

Substitusikan $x equals fraction numerator x to the power of apostrophe plus 4 over denominator 3 end fraction space dan straight space y equals fraction numerator y to the power of apostrophe plus 2 over denominator 3 end fraction space$

ke persamaan , didapat

$open parentheses fraction numerator x to the power of apostrophe plus 4 over denominator 3 end fraction minus 1 close parentheses squared plus open parentheses fraction numerator y to the power of apostrophe plus 2 over denominator 3 end fraction minus 3 close parentheses squared equals 10 open parentheses fraction numerator x to the power of apostrophe plus 1 over denominator 3 end fraction close parentheses squared plus open parentheses fraction numerator y to the power of apostrophe minus 7 over denominator 3 end fraction close parentheses squared equals 10 fraction numerator left parenthesis x squared plus 2 x plus 1 right parenthesis over denominator 9 end fraction plus fraction numerator left parenthesis y squared minus 14 y plus 49 right parenthesis over denominator 9 end fraction equals 10 space$