Perhatikan reaksi di bawah ini!   CH3​OH(g)+23​O2​(g)→CO2​(g)+2H2​O(g)H2​(g)+21​O2​(g)→H2​O(g)H2​CO(g)+O2​(g)→CO2​(g)+H2​O(g)​ΔH0=−676 kJ mol−1ΔH0=−242 kJ mol−1 ΔH0=−520 kJ mol−1 ​​       Dari data tersebut dapat diketahui bahwa perubahan entalpi reaksi H2​CO(g)+H2​(g)→CH3​OH(g) adalah ....   (SIMAK UI 2016)

Pertanyaan

Perhatikan reaksi di bawah ini!
 

Error converting from MathML to accessible text.    
 

Dari data tersebut dapat diketahui bahwa perubahan entalpi reaksi begin mathsize 14px style H subscript 2 C O open parentheses g close parentheses and H subscript 2 open parentheses g close parentheses yields C H subscript 3 O H open parentheses g close parentheses end style adalah ....undefined 

(SIMAK UI 2016)

  1. negative sign 46 space kJ space mol to the power of negative sign 1 end exponent 

  2. negative sign 86 space kJ space mol to the power of negative sign 1 end exponent

  3. plus 86 space kJ space mol to the power of negative sign 1 end exponent

  4. negative sign 172 space kJ space mol to the power of negative sign 1 end exponent

  5. plus 172 space kJ space mol to the power of negative sign 1 end exponent

S. Ardanari

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah B.

Pembahasan

Soal tersebut dapat kita selesaikan dengan menggunakan Hukum Hess.

Reaksi baris pertama dibalik.
Reaksi baris kedua tetap.
Reaksi baris ketiga tetap.
 

down diagonal strike CO subscript 2 left parenthesis straight g right parenthesis end strike plus down diagonal strike 2 straight H subscript 2 straight O left parenthesis g right parenthesis end strike rightwards arrow CH subscript 3 OH left parenthesis straight g right parenthesis plus down diagonal strike 3 over 2 straight O subscript 2 left parenthesis straight g right parenthesis end strike space space space space space space space straight capital delta H to the power of 0 equals plus 676 blank kJ blank mol to the power of negative 1 end exponent straight H subscript 2 left parenthesis straight g right parenthesis plus down diagonal strike 1 half straight O subscript 2 left parenthesis straight g right parenthesis end strike rightwards arrow down diagonal strike straight H subscript 2 straight O left parenthesis straight g right parenthesis end strike    space space space space space space space space space space space space space space space space space space space space space space space space space space space space space straight capital delta H to the power of italic 0 equals negative 242 blank kJ blank mol to the power of negative 1 end exponent straight H subscript 2 CO left parenthesis straight g right parenthesis plus down diagonal strike straight O subscript 2 left parenthesis straight g right parenthesis end strike rightwards arrow down diagonal strike CO subscript 2 left parenthesis straight g right parenthesis end strike plus down diagonal strike straight H subscript 2 straight O left parenthesis straight g right parenthesis end strike    space space space space space space space space space space space space straight capital delta H to the power of 0 equals negative 520 blank kJ blank mol to the power of negative 1 end exponent space space 


Perubahan entalpi reaksi begin mathsize 14px style H subscript 2 C O open parentheses g close parentheses and H subscript 2 open parentheses g close parentheses yields C H subscript 3 O H open parentheses g close parentheses end style adalah sebagai berikut.


straight capital delta H equals left parenthesis 676 space kJ. mol to the power of negative 1 end exponent right parenthesis plus left parenthesis negative 242 space kJ. mol to the power of negative 1 end exponent right parenthesis plus left parenthesis negative 520 space kJ. mol to the power of negative 1 end exponent right parenthesis straight capital delta H equals negative 86 space kJ. mol to the power of negative 1 end exponent  


Jadi, jawaban yang tepat adalah B.

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Nilai △Hf0 (kJ mol−1) untuk Ba2+(aq) = +540 dan SO42−​(aq) = −910. Jika entalpi reaksi pengendapan BaSO4​(s) adalah 30 kJ, maka entalpi pembentukan standar (s) adalah ....  (SBMPTN 2014)

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