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Perhatikan reaksi berikut. 2 1 ​ N 2 ​ ( g ) + 2 3 ​ H 2 ​ ( g ) → NH 3 ​ ( g ) △ H = − 437 , 5 kJ mol − 1 Jika diketahui D N − N ​ = 163 kJ mol -1 dan D H − H ​ = 436 kJ mol -1 , energi ikatan rata-rata N − H adalah ...

Perhatikan reaksi berikut.

 

Jika diketahui = 163 kJ mol-1 dan = 436 kJ mol-1, energi ikatan rata-rata  adalah ...

  1. +391 kJ mol-1space

  2. +418 kJ mol-1spacespace

  3. +495 kJ mol-1spacespace

  4. +894 kJ mol-1space

  5. +1 .173 kJ mol-1spacespace

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A. Nurul

Master Teacher

Mahasiswa/Alumni UIN Syarif Hidayatullah Jakarta

Jawaban terverifikasi

Jawaban

jawaban benar adalah A.

jawaban benar adalah A.

Pembahasan

struktur reaksi : menentukan nilai energi ikatan : Jadi, jawaban benar adalah A.

struktur reaksi :

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space H space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space I begin inline style 1 half end style N bond N plus begin inline style 3 over 2 end style H bond H yields N bond H space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space I space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space H

menentukan nilai energi ikatan N bond H :

increment H space space space space space equals sum energi space ikatan space reaktan minus sign sum energi space ikatan space reaktan increment H space space space space space equals left square bracket left parenthesis begin inline style 1 half end style cross times italic D subscript N bond N end subscript right parenthesis plus left parenthesis begin inline style 1 half end style begin inline style cross times end style begin inline style italic D subscript H bond H end subscript end style begin inline style right parenthesis end style begin inline style right square bracket end style begin inline style negative sign end style begin inline style left square bracket end style begin inline style left parenthesis end style begin inline style 3 end style begin inline style cross times end style begin inline style italic D subscript N bond H end subscript end style begin inline style right parenthesis end style begin inline style right square bracket end style begin inline style negative sign end style begin inline style 437 end style begin inline style comma end style begin inline style 5 end style begin inline style equals end style begin inline style left square bracket end style begin inline style left parenthesis end style begin inline style 1 half end style begin inline style cross times end style begin inline style 163 end style begin inline style right parenthesis end style begin inline style plus end style begin inline style left parenthesis end style begin inline style 3 over 2 end style begin inline style cross times end style begin inline style 436 end style begin inline style right square bracket end style begin inline style negative sign end style begin inline style left square bracket end style begin inline style left parenthesis end style begin inline style 3 end style begin inline style cross times end style begin inline style italic D subscript N bond H end subscript end style begin inline style right parenthesis end style begin inline style right square bracket end style minus sign begin inline style 437 end style begin inline style comma end style begin inline style 5 end style begin inline style equals end style 81 comma 5 begin inline style plus end style 654 minus sign begin inline style left square bracket end style begin inline style left parenthesis end style begin inline style 3 end style begin inline style cross times end style begin inline style italic D subscript N bond H end subscript end style begin inline style right parenthesis end style begin inline style right square bracket end style minus sign begin inline style 437 end style begin inline style comma end style begin inline style 5 end style begin inline style negative sign end style 81 comma 5 begin inline style negative sign end style 654 equals minus sign begin inline style left square bracket end style begin inline style left parenthesis end style begin inline style 3 end style begin inline style cross times end style begin inline style italic D subscript N bond H end subscript end style begin inline style right parenthesis end style begin inline style right square bracket end style minus sign 1173 space space space space space space space space space space space space space space space space equals minus sign begin inline style left square bracket end style begin inline style left parenthesis end style begin inline style 3 end style begin inline style cross times end style begin inline style italic D subscript N bond H end subscript end style begin inline style right parenthesis end style begin inline style right square bracket end style begin inline style italic D subscript N bond H end subscript end style space space space space space space space space space space space space space space space space space space space begin inline style equals end style 1173 over 3 begin inline style italic space end style begin inline style italic D subscript N italic bond H end subscript end style begin inline style italic space end style begin inline style italic space end style begin inline style italic space end style begin inline style italic space end style begin inline style italic space end style begin inline style italic space end style begin inline style italic space end style begin inline style italic space end style begin inline style italic space end style begin inline style italic space end style begin inline style italic space end style begin inline style italic space end style begin inline style italic space end style begin inline style italic space italic space italic space end style begin inline style equals end style begin inline style plus end style begin inline style 391 end style begin inline style space end style begin inline style kJ end style begin inline style space end style begin inline style mol to the power of negative sign 1 end exponent end style 

Jadi, jawaban benar adalah A.

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Diketahui reaksi berikut. H O I ∥ H − C − H + 2 O = O → C + 2 H − O − H I ∥ H O Diketahui perubahan entalpi sebesar -109 kJ serta energi ikatan C = O , H − O , dan O = O berturut-turut 243 kJ mo...

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