Roboguru

Perhatikan reaksi berikut!     Jika 150 mL larutan   0,05 M direaksikan dengan 100 mL larutan NaOH 0,4 M, maka dari reaksi tersebut akan tersisa....

Pertanyaan

Perhatikan reaksi berikut!

H subscript 2 S O subscript 4 left parenthesis italic a italic q right parenthesis plus Na O H left parenthesis italic a italic q right parenthesis yields Na subscript 2 S O subscript 4 left parenthesis italic a italic q right parenthesis plus 2 H subscript 2 O open parentheses italic l close parentheses   

Jika 150 mL larutan H subscript 2 S O subscript 4  0,05 M direaksikan dengan 100 mL larutan NaOH 0,4 M, maka dari reaksi tersebut akan tersisa....

  1. 3 comma 5 cross times 10 to the power of negative sign 2 end exponent space mol space H subscript 2 S O subscript 4 

  2. 5 cross times 10 to the power of negative sign 3 end exponent space mol space H subscript 2 S O subscript 4 

  3. 7 comma 5 cross times 10 to the power of negative sign 2 end exponent space mol space Na O H 

  4. 5 cross times 10 to the power of negative sign 3 end exponent space mol space Na O H 

  5. 2 comma 5 cross times 10 to the power of negative sign 2 end exponent space mol space Na O H 

Pembahasan Soal:

Hitung mol masing masing pereaksi.

table attributes columnalign right center left columnspacing 0px end attributes row cell n space H subscript 2 S O subscript 4 end cell equals cell M cross times V end cell row blank equals cell 0 comma 05 cross times 0 comma 15 L end cell row blank equals cell 0 comma 0075 space mol space end cell row blank blank blank row cell n space Na O H end cell equals cell M cross times V end cell row blank equals cell 0 comma 4 cross times 0 comma 1 L end cell row blank equals cell 0 comma 04 space mol end cell end table  

Setarakan persamaan reaksi, dan buat perbandingan mol bereaksi

bold space bold space bold space bold space bold space bold space bold space bold space bold space bold space H subscript bold 2 S O subscript bold 4 bold space bold space bold space bold space bold plus bold space bold space bold space bold 2 Na O H bold space bold space bold rightwards arrow bold space bold space Na subscript bold 2 S O subscript bold 4 bold space bold space bold space bold plus bold space bold space bold space bold space bold space bold 2 H subscript bold 2 O M space space space space space space 0 comma 0075 space space space space space space space space space space space space 0 comma 04 B space space space space space space space 0 comma 0075 space space space space space space space space space space space 0 comma 015 space space space space space space space space space space space space 0 comma 0075 space space space space space space space space space space space space space space space space 0 comma 015 S space space space space space space space space minus sign space space space space space space space space space space space space space space space space space space 0 comma 025 space space space space space space space space space space space space 0 comma 0075 space space space space space space space space space space space space space space space space space 0 comma 015 

 Maka mol pereaksi yang bersisa adalah 0,025 NaOH (E)

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 27 April 2021

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