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Perhatikan rangkaian listrik berikut!

Berdasarkan rangkaian listrik tersebut, pernyataan berikut yang benar adalah ....space space 

  1. Hambatan total pada rangkaian adalah 1,5 ohm.

  2. Arus total pada rangkaian adalah 1,6 A.

  3. Daya arus yang dihasilkan pada Radalah 2,43 W.

  4. Daya yang dihasilkan pada Rsama dengan daya pada R4.

  5. Usaha yang dilakukan pada Rselama 5 menit adalah 12,15 J.space space 

A. Aulia

Master Teacher

Jawaban terverifikasi

Jawaban

usaha yang dilakukan pada R4 selama 5 menit adalah 729 J.

Pembahasan

Diketahui:

table attributes columnalign right center left columnspacing 0px end attributes row cell R subscript 1 end cell equals cell 1 comma 5 space straight capital omega space space space space R subscript 2 equals 6 space straight capital omega space end cell row cell R subscript 3 end cell equals cell 6 space straight capital omega space space space space space space space R subscript 4 equals 3 space straight capital omega space end cell row cell R subscript 5 end cell equals cell 2 space straight capital omega space space space space space space space E subscript 1 equals 3 space straight V end cell row cell E subscript 2 end cell equals cell 6 space straight V end cell end table

Ditanya: 

straight a. space R subscript T o t a l end subscript space ? straight b. space I subscript T o t a l end subscript space ? straight c. space P subscript 4 space ? straight d. space P subscript 3 equals P subscript 4 space ? straight e. space W space pada space R subscript 4 ?

Jawab:

table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell straight a. space R subscript T o t a l end subscript end cell row blank blank cell R subscript 2 comma space end subscript R subscript 3 comma end subscript space R subscript 4 space end subscript paralel end cell row cell 1 over R subscript P end cell equals cell 1 over R subscript 2 plus 1 over R subscript 3 plus 1 over R subscript 4 end cell row blank equals cell 1 over 6 plus 1 over 6 plus 1 third end cell row blank equals cell fraction numerator 1 plus 1 plus 2 over denominator 6 end fraction end cell row cell 1 over R subscript P end cell equals cell 4 over 6 end cell row cell R subscript P end cell equals cell 6 over 4 end cell row blank equals cell 3 over 2 end cell row cell R subscript P end cell equals cell 1 comma 5 space capital omega end cell row blank blank blank row blank blank cell R subscript 1 comma space end subscript R subscript P comma end subscript space R subscript 5 space Seri end cell row cell R subscript S end cell equals cell R subscript 1 plus R subscript P plus R subscript 5 end cell row blank equals cell 1 comma 5 plus 1 comma 5 plus 2 end cell row blank equals cell 5 space straight capital omega end cell row cell R subscript T o t a l end subscript end cell equals cell R subscript S equals 5 straight capital omega end cell end table

Jadi, hambatan total pada rangkaian adalah 5 bold capital omega

straight b. space I subscript T o t a l end subscript space ? Gunakan space Hukum space 2 space Kirchoff comma space 1 space Loop plus-or-minus capital sigma E plus-or-minus I open parentheses R plus r close parentheses equals 0 open parentheses negative E subscript 1 minus E subscript 2 close parentheses plus I left parenthesis R subscript 1 plus R subscript P plus R subscript 5 right parenthesis equals 0 open parentheses negative 3 minus 6 close parentheses plus I left parenthesis 1 comma 5 plus 1 comma 5 plus 2 right parenthesis equals 0 minus 9 plus I open parentheses 5 close parentheses equals 0 I open parentheses 5 close parentheses equals 9 I equals 9 over 5 I equals 1 comma 8 space straight A

Jadi, kuat arus total rangkaian adalah 1,8 A.

table attributes columnalign right center left columnspacing 0px end attributes row cell straight c. space P end cell equals cell I squared cross times R end cell row cell I subscript 2 space colon I subscript 3 space colon space I subscript 4 space end cell equals cell 1 over R subscript 2 colon 1 over R subscript 3 colon 1 over R subscript 4 end cell row blank equals cell 1 over 6 colon 1 over 6 colon 1 third end cell row blank equals cell 1 over 6 colon 1 over 6 colon 2 over 6 end cell row cell I subscript 2 space colon space I subscript 3 space colon space I subscript 4 end cell equals cell 1 space colon 1 space colon space 2 end cell row cell I subscript 2 end cell equals cell 1 fourth cross times I subscript T o t a l end subscript end cell row blank equals cell 1 fourth cross times 1 comma 8 end cell row blank equals cell 0 comma 45 space straight A end cell row blank blank blank row cell I subscript 3 end cell equals cell 1 fourth cross times I subscript T o t a l end subscript end cell row blank equals cell 1 fourth cross times 1 comma 8 end cell row blank equals cell 0 comma 45 space straight A end cell row blank blank blank row cell I subscript 4 end cell equals cell 2 over 4 cross times I subscript T o t a l end subscript end cell row blank equals cell 2 over 4 cross times 1 comma 8 end cell row blank equals cell 0 comma 9 space straight A end cell row blank blank blank row cell P subscript 4 end cell equals cell I subscript 4 squared cross times R subscript 4 end cell row blank equals cell 0.9 squared cross times R subscript 4 end cell row blank equals cell 0 comma 81 cross times 3 end cell row cell P subscript 4 end cell equals cell 2 comma 43 space watt end cell end table

Jadi, daya arus yang dihasilkan pada bold italic R subscript bold 4 adalah 2,43 watt.

table attributes columnalign right center left columnspacing 0px end attributes row cell d. space P end cell equals cell I squared cross times R end cell row cell P subscript 3 end cell equals cell I subscript 3 squared cross times R subscript 3 end cell row blank equals cell 0 comma 45 squared cross times R subscript 3 end cell row blank equals cell 0 comma 2025 cross times 6 end cell row cell P subscript 3 end cell equals cell 1 comma 215 space watt end cell end table

Jadi, daya yang dihasilkan R3 tidak sama dengan daya yang dihasilkan R4.

table attributes columnalign right center left columnspacing 0px end attributes row cell straight d. space W end cell equals cell P cross times t end cell row cell W subscript 4 end cell equals cell P subscript 4 cross times t end cell row blank equals cell 2 comma 43 cross times 300 end cell row blank equals cell 729 space straight J end cell end table

Jadi, usaha yang dilakukan pada R4 selama 5 menit adalah 729 J.

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