Perhatikan persamaan reaksi berikut! 2 NaHCO 3 ( g ) → Na 2 CO 3 ( g ) + H 2 O ( l ) + CO 2 ( g ) Diketahui: △ H f ∘ NaHCO 3 ( g ) = 95 kJ / mol , , , △ H f ∘ CO 2 ( g ) = 75 kJ / mol . Perubahan entalpi reaksi adalah ....

Question

Perhatikan persamaan reaksi berikut!

$2 NaHCO_{3} (g) \to Na_{2} CO_{3} (g) + H_{2} O (l) + CO_{2} (g)$

Diketahui:

$△ H_{f}^{\circ} NaHCO_{3} (g) = 95 kJ / mol$ ,

$\style{font-size:14px}\triangle{\style{font-size:14px}{\mathrm H}}_\style{font-size:14px}{\mathrm f}\style{font-size:14px}\textdegree\style{font-size:14px}\;{\style{font-size:14px}{\mathrm{Na}}}_\style{font-size:14px}2{\style{font-size:14px}{\mathrm{CO}}}_\style{font-size:14px}3\style{font-size:14px}(\style{font-size:14px}g\style{font-size:14px})\style{font-size:14px}=\style{font-size:14px}{120}\style{font-size:14px}\;\style{font-size:14px}{\mathrm{kJ}}\style{font-size:14px}/\style{font-size:14px}{\mathrm{mol}}$ ,

$\style{font-size:14px}\triangle{\style{font-size:14px}{\mathrm H}}_\style{font-size:14px}{\mathrm f}\style{font-size:14px}\textdegree\style{font-size:14px}\;{\style{font-size:14px}{\mathrm H}}_\style{font-size:14px}2\style{font-size:14px}{\mathrm O}\style{font-size:14px}(\style{font-size:14px}g\style{font-size:14px})\style{font-size:14px}=\style{font-size:14px}{80}\style{font-size:14px}\;\style{font-size:14px}{\mathrm{kJ}}\style{font-size:14px}/\style{font-size:14px}{\mathrm{mol}}$ ,

$△ H_{f}^{\circ} CO_{2} (g) = 75 kJ / mol$ .