Roboguru

Perhatikan gambar rangkaian RLC berikut ini!   Kuat arus efektif dari rangkaian adalah...

Pertanyaan

Perhatikan gambar rangkaian RLC berikut ini!

 

Kuat arus efektif dari rangkaian adalah...

Pembahasan Video:

Pembahasan Soal:

Diketahui:

R equals 12 space text Ω end text L equals 0 comma 075 space text H end text C equals 500 space mu F equals 500 space x space 10 to the power of negative 6 end exponent space text F end text omega equals 200 space text rad/s end text V m space equals space 26 space text V end text  

Ditanya: arus efektif...?

Pembahasan:

Hitung impedansi rangkaian

begin mathsize 14px style table attributes columnalign right right left end attributes row omega equals cell 200 rad over straight s end cell row cell X subscript L end cell equals cell omega L end cell row blank equals cell 200 cross times 0 , 075 end cell row blank equals cell 15 blank straight capital omega end cell row cell X subscript C end cell equals cell fraction numerator 1 over denominator omega C end fraction end cell row blank equals cell fraction numerator 1 over denominator 200 cross times 500 cross times 10 to the power of negative 6 end exponent end fraction end cell row blank equals cell 10 blank straight capital omega end cell row blank blank blank row straight Z equals cell square root of straight R squared plus open parentheses straight X subscript straight L minus straight X subscript straight C close parentheses squared end root end cell row blank equals cell square root of 12 squared plus open parentheses 15 minus 10 close parentheses squared end root end cell row blank equals cell 13 blank straight capital omega end cell end table end style 

Menghitung tegangan efektif

V subscript e f end subscript equals fraction numerator V subscript m over denominator square root of 2 end fraction equals fraction numerator 26 over denominator square root of 2 end fraction 

Hitung arus efektif

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell I subscript e f end subscript end cell equals cell V subscript e f end subscript over Z end cell row blank equals cell fraction numerator 26 over denominator 13 square root of 2 end fraction end cell row blank equals cell square root of bold 2 bold space bold A end cell end table end style  

Jadi, besarnya arus efektif sebesar square root of 2 text A end text.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 03 Agustus 2021

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved