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Perhatikan gambar rangkaian kapasitor ini!

Besar energi listrik pada kapasitor gabungan adalah....left parenthesis 1 space μF equals 10 to the power of negative 6 end exponent straight F right parenthesis

  1. begin mathsize 12px style 1 comma 44 cross times 10 to the power of negative 4 end exponent space J end style

  2. begin mathsize 12px style 2 comma 88 cross times 10 to the power of negative 4 end exponent space J end style

  3. begin mathsize 12px style 5 comma 76 cross times 10 to the power of negative 4 end exponent space J end style

  4. begin mathsize 12px style 7 comma 20 cross times 10 to the power of negative 4 end exponent space J end style

  5. begin mathsize 12px style 8 comma 34 cross times 10 to the power of negative 4 end exponent space J end style

E. Dwihermiati

Master Teacher

Mahasiswa/Alumni Universitas Pendidikan Indonesia

Jawaban terverifikasi

Pembahasan

Ada dua kapasitas kapasitor yang dipasang secara paralel. Maka:

begin mathsize 12px style C subscript p 1 end subscript equals 7 plus 5 equals 12 mu F  C subscript p 2 end subscript equals 4 plus 2 equals 6 mu F end style

Lalu, sekarang tinggal dirangkai secara seri semuanya.

begin mathsize 12px style 1 over C subscript s equals 1 over 12 plus 1 over 6 plus 1 fourth  fraction numerator begin display style 1 end style over denominator begin display style C subscript s end style end fraction equals fraction numerator begin display style 1 end style over denominator begin display style 12 end style end fraction plus fraction numerator begin display style 2 end style over denominator begin display style 12 end style end fraction plus fraction numerator begin display style 3 end style over denominator begin display style 12 end style end fraction  fraction numerator begin display style 1 end style over denominator begin display style C subscript s end style end fraction equals fraction numerator begin display style 6 end style over denominator begin display style 12 end style end fraction  C subscript s equals 12 over 6 equals 2 mu F equals 2 cross times 10 to the power of negative 6 end exponent F end style

Besarnya energi pada kapasitor setelah semuanya digabungkan adalah:

begin mathsize 12px style W equals 1 half C V squared  W subscript t o t a l end subscript equals 1 half C subscript t o t a l end subscript V subscript t o t a l end subscript superscript 2  W subscript t o t a l end subscript equals 1 half open parentheses 2 cross times 10 to the power of negative 6 end exponent close parentheses open parentheses 24 close parentheses squared equals 576 cross times 10 to the power of negative 6 end exponent space J  W subscript t o t a l end subscript equals 576 cross times 10 to the power of negative 6 end exponent space J  W subscript t o t a l end subscript equals 5 comma 76 cross times 10 to the power of negative 4 end exponent space J end style

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Tiga buah kapasitor disusun seperti pada gambar. Diketahui C1=2μF,C2=3μF,danC3=1F. Jika VAB​=12V, Muatan pada C1 dan C2 ....

3rb+

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