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Perhatikan data percobaan pencampuran Ca(NO3​)2​ dan larutan H2​C2​O4​ berikut!     Jika harga Ksp​ CaC2​O4​ = 4 x 10−9, pernyataan yang benar adalah ...

Pertanyaan

Perhatikan data percobaan pencampuran begin mathsize 14px style Ca open parentheses N O subscript 3 close parentheses subscript 2 end style dan larutan begin mathsize 14px style H subscript 2 C subscript 2 O subscript 4 end style berikut!
 


 

Jika harga begin mathsize 14px style K subscript italic s italic p end subscript space Ca C subscript 2 O subscript 4 space equals space 4 space x space 10 to the power of negative sign 9 end exponent end style, pernyataan yang benar adalah ... 

  1. Campuran 3) tepat akan mengendap karena begin mathsize 14px style italic Q subscript italic s italic p end subscript space equals space K subscript italic s italic p end subscript end style 

  2. Campuran 2) belum menghasilkan endapan karena begin mathsize 14px style italic Q subscript italic s italic p end subscript space greater than space K subscript italic s italic p end subscript end style  

  3. Campuran 1) menghasilkan endapan karena begin mathsize 14px style italic Q subscript italic s italic p end subscript space less than space K subscript italic s italic p end subscript end style   

  4. Campuran 3) sudah menghasilkan endapan karena begin mathsize 14px style italic Q subscript italic s italic p end subscript space equals space K subscript italic s italic p end subscript end style 

  5. Campuran 2)  menghasilkan endapan karena begin mathsize 14px style italic Q subscript italic s italic p end subscript space equals space K subscript italic s italic p end subscript end style  

I. Solichah

Master Teacher

Jawaban terverifikasi

Jawaban

  berdasarkan penjelasan di atas tidak ada jawaban yang benar. 

Pembahasan

Larutan tepat jenuh adalah  ketika hasil kali ion-ionnya sama dengan nilai Ksp larutan tersebut. Tepat jenuh terjadi ketika tidak terjadi proses pelarutan dan menuju pengendapan, tetapi belum terjadi pengendapan. 


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Campuran 1)

   begin mathsize 14px style V space Ca open parentheses N O subscript 3 close parentheses subscript 2 equals 100 space mL M space Ca open parentheses N O subscript 3 close parentheses subscript 2 equals 10 to the power of negative sign 5 end exponent V space H subscript 2 C subscript 2 O subscript 4 equals 100 space mL M space H subscript 2 C subscript 2 O subscript 4 equals 10 to the power of negative sign 1 end exponent V space total space equals space 200 space mL space equals space 0 comma 2 space L end style  


Menentukan konsentrasi begin mathsize 14px style Ca open parentheses N O subscript 3 close parentheses subscript 2 end style setelah pencampuran


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell M subscript sebelum cross times V subscript sebelum space end subscript end cell equals cell M subscript setelah cross times V subscript setelah space end subscript end cell row cell 10 to the power of negative sign 5 end exponent cross times 0 comma 1 end cell equals cell M subscript setelah cross times 0 comma 2 end cell row cell 10 to the power of negative sign 6 end exponent end cell equals cell M subscript setelah cross times 0 comma 2 end cell row cell M subscript setelah end cell equals cell fraction numerator 10 to the power of negative sign 6 end exponent over denominator 0 comma 2 end fraction end cell row blank equals cell 5 cross times 10 to the power of negative sign 6 end exponent end cell end table end style 

 begin mathsize 14px style Ca open parentheses N O subscript 3 close parentheses subscript 2 yields Ca to the power of 2 plus sign and 2 N O subscript 3 to the power of minus sign 5 cross times 10 to the power of negative sign 6 end exponent space space space space 5 cross times 10 to the power of negative sign 6 end exponent space space space 10 to the power of negative sign 5 end exponent end style 


Menentukan konsentrasi larutan begin mathsize 14px style H subscript 2 C subscript 2 O subscript 4 end style setelah pencampuran


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell M subscript sebelum cross times V subscript sebelum space end subscript end cell equals cell M subscript setelah cross times V subscript setelah space end subscript end cell row cell 10 to the power of negative sign 1 end exponent cross times 0 comma 1 end cell equals cell M subscript setelah cross times 0 comma 2 end cell row cell 10 to the power of negative sign 2 end exponent end cell equals cell M subscript setelah cross times 0 comma 2 end cell row cell M subscript setelah end cell equals cell fraction numerator 10 to the power of negative sign 2 end exponent over denominator 0 comma 2 end fraction end cell row blank equals cell 5 cross times 10 to the power of negative sign 2 end exponent end cell end table end style 

begin mathsize 14px style H subscript 2 C subscript 2 O subscript 4 yields 2 H to the power of plus sign and C subscript 2 O subscript 4 to the power of 2 minus sign 5 cross times 10 to the power of negative sign 2 end exponent space space space space 10 to the power of negative sign 1 end exponent space space space space 5 cross times 10 to the power of negative sign 2 end exponent end style 


Menentukan nilai begin mathsize 14px style Q subscript sp end style 


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell Q subscript sp space Ca C subscript 2 O subscript 4 end cell equals cell open square brackets Ca to the power of 2 plus sign close square brackets open square brackets C subscript 2 O subscript 4 to the power of 2 minus sign close square brackets end cell row blank equals cell 5 cross times 10 to the power of negative sign 6 end exponent cross times 5 cross times 10 to the power of negative sign 2 end exponent end cell row blank equals cell 25 cross times 10 to the power of negative sign 8 end exponent end cell row blank equals cell 2 comma 5 cross times 10 to the power of negative sign 7 end exponent end cell end table end style  


Membandingkan nilai begin mathsize 14px style Q subscript sp space dengan space K subscript sp end style 

begin mathsize 14px style K subscript sp equals 4 cross times 10 to the power of negative sign 9 end exponent end style 

begin mathsize 14px style Q subscript sp equals 2 comma 5 cross times 10 to the power of negative sign 7 end exponent end style 


Karena begin mathsize 14px style Q subscript sp greater than K subscript sp end style  maka terbentuk endapan.

Campuran 2)

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell V space Ca open parentheses N O subscript 3 close parentheses subscript 2 end cell equals cell 50 space mL end cell row cell M space Ca open parentheses N O subscript 3 close parentheses subscript 2 end cell equals cell 2 cross times 10 to the power of negative sign 5 end exponent end cell row cell V space H subscript 2 C subscript 2 O subscript 4 end cell equals cell 50 space mL end cell row cell M space H subscript 2 C subscript 2 O subscript 4 end cell equals cell 2 cross times 10 to the power of negative sign 6 end exponent end cell row cell V space total space end cell equals cell space 100 space mL space equals space 0 comma 1 space L end cell end table end style 


Menentukan konsentrasi undefined setelah pencampuran


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell M subscript sebelum cross times V subscript sebelum space end subscript end cell equals cell M subscript setelah cross times V subscript setelah space end subscript end cell row cell 2 cross times 10 to the power of negative sign 5 end exponent cross times 0 comma 05 end cell equals cell M subscript setelah cross times 0 comma 1 end cell row cell 10 to the power of negative sign 6 end exponent end cell equals cell M subscript setelah cross times 0 comma 1 end cell row cell M subscript setelah end cell equals cell fraction numerator 10 to the power of negative sign 6 end exponent over denominator 0 comma 1 end fraction end cell row blank equals cell 10 to the power of negative sign 5 end exponent end cell end table end style 

begin mathsize 14px style Ca open parentheses N O subscript 3 close parentheses subscript 2 yields Ca to the power of 2 plus sign and 2 N O subscript 3 to the power of minus sign 10 to the power of negative sign 5 end exponent space space space space space space space space space space space 10 to the power of negative sign 5 end exponent space space space space space 2 cross times 10 to the power of negative sign 5 end exponent end style 


Menentukan konsentrasi undefined setelah pencampuran


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell M subscript sebelum cross times V subscript sebelum space end subscript end cell equals cell M subscript setelah cross times V subscript setelah space end subscript end cell row cell 2 cross times 10 to the power of negative sign 6 end exponent cross times 0 comma 05 end cell equals cell M subscript setelah cross times 0 comma 1 end cell row cell 10 to the power of negative sign 7 end exponent end cell equals cell M subscript setelah cross times 0 comma 1 end cell row cell M subscript setelah end cell equals cell fraction numerator 10 to the power of negative sign 7 end exponent over denominator 0 comma 1 end fraction end cell row blank equals cell 10 to the power of negative sign 6 end exponent end cell end table end style  

begin mathsize 14px style H subscript 2 C subscript 2 O subscript 4 yields 2 H to the power of plus sign and C subscript 2 O subscript 4 to the power of 2 minus sign 10 to the power of negative sign 6 end exponent space space space space space space space 2 cross times 10 to the power of negative sign 6 end exponent space space 10 to the power of negative sign 6 end exponent end style  


Menentukan nilai undefined 


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell Q subscript sp space Ca C subscript 2 O subscript 4 end cell equals cell open square brackets Ca to the power of 2 plus sign close square brackets open square brackets C subscript 2 O subscript 4 to the power of 2 minus sign close square brackets end cell row blank equals cell 10 to the power of negative sign 5 end exponent cross times 10 to the power of negative sign 6 end exponent end cell row blank equals cell 10 to the power of negative sign 11 end exponent end cell end table end style  


Membandingkan nilai begin mathsize 14px style Q subscript sp end style dengan begin mathsize 14px style K subscript sp end style 

begin mathsize 14px style K subscript sp equals 4 cross times 10 to the power of negative sign 9 end exponent Q subscript sp equals 10 to the power of negative sign 11 end exponent end style  


Karena undefined maka tidak terbentuk endapan

Campuran 3)


 begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell V space Ca open parentheses N O subscript 3 close parentheses subscript 2 end cell equals cell 100 space mL end cell row cell M space Ca open parentheses N O subscript 3 close parentheses subscript 2 end cell equals cell 8 cross times 10 to the power of negative sign 6 end exponent end cell row cell V space H subscript 2 C subscript 2 O subscript 4 end cell equals cell 100 space mL end cell row cell M space H subscript 2 C subscript 2 O subscript 4 end cell equals cell 8 cross times 10 to the power of negative sign 6 end exponent end cell row cell V space total space end cell equals cell space 200 space mL space equals space 0 comma 2 space L end cell end table end style


Menentukan konsentrasi Error converting from MathML to accessible text. setelah pencampuran


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell M subscript sebelum cross times V subscript sebelum space end subscript end cell equals cell M subscript setelah cross times V subscript setelah space end subscript end cell row cell 8 cross times 10 to the power of negative sign 6 end exponent cross times 0 comma 1 end cell equals cell M subscript setelah cross times 0 comma 2 end cell row cell 8 cross times 10 to the power of negative sign 7 end exponent end cell equals cell M subscript setelah cross times 0 comma 2 end cell row cell M subscript setelah end cell equals cell fraction numerator 8 cross times 10 blank to the power of negative sign 7 end exponent over denominator 0 comma 2 end fraction end cell row blank equals cell 4 cross times 10 to the power of negative sign 6 end exponent end cell end table end style 

begin mathsize 14px style Ca open parentheses N O subscript 3 close parentheses subscript 2 yields Ca to the power of 2 plus sign and 2 N O subscript 3 to the power of minus sign 4 cross times 10 to the power of negative sign 6 end exponent space space space space space space 4 cross times 10 to the power of negative sign 6 end exponent space space space space 8 cross times 10 to the power of negative sign 6 end exponent end style  


Menentukan konsentrasi undefined setelah pencampuran


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell M subscript sebelum cross times V subscript sebelum space end subscript end cell equals cell M subscript setelah cross times V subscript setelah space end subscript end cell row cell 8 cross times 10 to the power of negative sign 6 end exponent cross times 0 comma 1 end cell equals cell M subscript setelah cross times 0 comma 2 end cell row cell 8 cross times 10 to the power of negative sign 7 end exponent end cell equals cell M subscript setelah cross times 0 comma 2 end cell row cell M subscript setelah end cell equals cell fraction numerator 8 cross times 10 to the power of negative sign 7 end exponent over denominator 0 comma 2 end fraction end cell row blank equals cell 4 cross times 10 to the power of negative sign 6 end exponent end cell end table end style 

begin mathsize 14px style H subscript 2 C subscript 2 O subscript 4 yields 2 H to the power of plus sign and C subscript 2 O subscript 4 to the power of 2 minus sign 4 cross times 10 to the power of negative sign 6 end exponent space space space 8 cross times 10 to the power of negative sign 6 end exponent space space space 4 cross times 10 to the power of negative sign 6 end exponent end style  


Menentukan nilai undefined 


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell Q subscript sp space Ca C subscript 2 O subscript 4 end cell equals cell open square brackets Ca to the power of 2 plus sign close square brackets open square brackets C subscript 2 O subscript 4 to the power of 2 minus sign close square brackets end cell row blank equals cell 4 cross times 10 to the power of negative sign 6 end exponent cross times 4 cross times 10 to the power of negative sign 6 end exponent end cell row blank equals cell 16 cross times 10 to the power of negative sign 12 end exponent end cell row blank equals cell 1 comma 6 cross times 10 to the power of negative sign 11 end exponent end cell end table end style  


Membandingkan nilai undefined dengan undefined 

begin mathsize 14px style K subscript sp equals 4 cross times 10 to the power of negative sign 9 end exponent Q subscript sp equals 1 comma 6 cross times 10 to the power of negative sign 11 end exponent end style 


Karena undefined maka tidak terbentuk endapan.

Dengan demikian,  berdasarkan penjelasan di atas tidak ada jawaban yang benar. 

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