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Pada suhu  terjadi reaksi kesetimbangan di atas, m...

Pada suhu begin mathsize 14px style T degree C end style terjadi reaksi kesetimbangan di atas, mula-mula direaksikan 4 mol gas NO dan 2 mol gas begin mathsize 14px style O subscript 2 end style dalam bejana tertutup. Jika saat setimbang terdapat 2 mol gas begin mathsize 14px style N O subscript 2 end style dan tekanan total gas dalam wadah tersebut sebesar 3 atm, tentukan harga begin mathsize 14px style K subscript p end style reaksi tersebut.

Jawaban:

Persamaan reaksi yang terjadi:

 

mol space total space equals space mol space N O space plus space mol space O subscript 2 space plus space mol space N O subscript 2 space space space space space space space space space space space space space space equals space 2 space mol space plus space 1 space mol space plus space 2 space mol space space space space space space space space space space space space space space equals space 5 space mol 

Menentukan nilai tekanan:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell P subscript NO space end cell equals cell space n subscript NO over n subscript total cross times P subscript total end cell row blank equals cell space 2 over 5 cross times 3 end cell row blank equals cell space 1 comma 2 space atm end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell P subscript O subscript 2 end subscript space end cell equals cell space n subscript O subscript 2 end subscript over n subscript total cross times P subscript total end cell row blank equals cell space 1 fifth cross times 3 end cell row blank equals cell space 0 comma 6 space atm end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell P subscript N O subscript 2 end subscript space end cell equals cell space n subscript N O subscript 2 end subscript over n subscript total cross times P subscript total end cell row blank equals cell space 2 over 5 cross times 3 end cell row blank equals cell space 1 comma 2 space atm end cell end table end style 

Maka nilai begin mathsize 14px style K subscript p end style:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript p space end cell equals cell space fraction numerator open parentheses P subscript N O subscript 2 end subscript close parentheses squared over denominator open parentheses P subscript NO close parentheses squared open parentheses P subscript O subscript 2 end subscript close parentheses end fraction end cell row blank equals cell space space fraction numerator open parentheses 1 comma 2 close parentheses squared over denominator open parentheses 1 comma 2 close parentheses squared open parentheses 0 comma 6 close parentheses end fraction end cell row blank equals cell space 1 comma 67 end cell end table end style 

Jadi, jawaban yang benar begin mathsize 14px style K subscript p end style = 1,67.

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