Pertanyaan

Pada reaksi kesetimbangan CO ( g ) + 3 H 2 ( g ) ⇋ C H 4 ( g ) + H 2 O ( g ) diperoleh data sebagai berikut: Harga Kc dari reaksi tersebut adalah...

Pada reaksi kesetimbangan $CO (g) + 3 H_{2} (g) ⇋ C H_{4} (g) + H_{2} O (g)$ diperoleh data sebagai berikut:

Harga Kc dari reaksi tersebut adalah...

$size 12px K size 12px c size 12px equals fraction numerator open square brackets size 12px 0 size 12px comma size 12px 05 close square brackets open square brackets size 12px 0 size 12px comma size 12px 05 close square brackets over denominator open square brackets size 12px 0 size 12px comma size 12px 15 close square brackets open square brackets size 12px 0 size 12px comma size 12px 15 close square brackets end fraction$
$begin mathsize 12px style K c equals fraction numerator open square brackets 0 comma 05 close square brackets open square brackets 0 comma 05 close square brackets over denominator open square brackets 0 comma 20 close square brackets open square brackets 0 comma 30 close square brackets end fraction end style$
$begin mathsize 12px style K c equals fraction numerator open square brackets 0 comma 05 close square brackets open square brackets 0 comma 05 close square brackets over denominator open square brackets 0 comma 20 close square brackets open square brackets 0 comma 30 close square brackets cubed end fraction end style$
$begin mathsize 12px style K c equals fraction numerator open square brackets 0 comma 05 close square brackets open square brackets 0 comma 05 close square brackets over denominator open square brackets 0 comma 15 close square brackets open square brackets 0 comma 15 close square brackets cubed end fraction end style$
$begin mathsize 12px style K c equals fraction numerator open square brackets 0 comma 15 close square brackets open square brackets 0 comma 15 close square brackets cubed over denominator open square brackets 0 comma 05 close square brackets open square brackets 0 comma 05 close square brackets end fraction end style$

D. Ayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Pembahasan

$begin mathsize 12px style space space space space space space C O space left parenthesis g right parenthesis plus 3 H subscript 2 space left parenthesis g right parenthesis leftwards harpoon over rightwards harpoon C H subscript 4 space left parenthesis g right parenthesis plus H subscript 2 O space left parenthesis g right parenthesis S equals 0 comma 15 space M space space space space 0 comma 15 space M space space space space space 0 comma 05 space M space space space space space space 0 comma 05 space M K c equals open square brackets p r o d u k close square brackets to the power of k o e f i s i e n end exponent over open square brackets r e a k tan close square brackets to the power of k o e f i s i e n end exponent K c equals fraction numerator open square brackets C H subscript 4 close square brackets to the power of 1 open square brackets H subscript 2 O close square brackets to the power of 1 over denominator open square brackets C O close square brackets to the power of 1 cross times open square brackets H subscript 2 close square brackets cubed end fraction K c equals fraction numerator open square brackets 0 comma 05 close square brackets to the power of 1 open square brackets 0 comma 05 close square brackets to the power of 1 over denominator open square brackets 0 comma 15 close square brackets to the power of 1 cross times open square brackets 0 comma 15 close square brackets cubed end fraction end style$

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