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Pada reaksi 2 A + B → 2 C , didapatkan data laju reaksi sebagai berikut. Pernyataan yang benar berdasarkan data hasil percobaan tersebut adalah ...

Pada reaksi , didapatkan data laju reaksi sebagai berikut.
 


 

Pernyataan yang benar berdasarkan data hasil percobaan tersebut adalah ...

  1. Persamaan laju reaksinya r = k [A].

  2. Orde reaksi terhadap A adalah begin mathsize 14px style 1 half end style.

  3. Orde reaksi terhadap B adalah 2.

  4. Satuan niiai k adalah begin mathsize 14px style dm to the power of negative sign 3 end exponent space detik to the power of negative sign 1 end exponent end style.undefined

  5. Orde reaksi total adalah 4.

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I. Solichah

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Pembahasan

Pembahasan

Orde [A] pada percobaan 1 dan 2 Orde [B] pada percobaan 1 dan 3 Orde reaksi total = 3 persamaan laju reaksinya adalah Jadi, jawaban yang benar adalah C.

Orde [A] pada percobaan 1 dan 2

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator v 1 over denominator v 2 end fraction end cell equals cell italic k over italic k cross times open parentheses open square brackets A close square brackets subscript 1 over open square brackets A close square brackets subscript 2 close parentheses to the power of x cross times open parentheses open square brackets B close square brackets subscript 1 over open square brackets B close square brackets subscript 2 close parentheses to the power of y end cell row cell fraction numerator begin display style bevelled fraction numerator 1 over denominator t 1 end fraction end style over denominator begin display style bevelled fraction numerator 1 over denominator t 2 end fraction end style end fraction end cell equals cell italic k over italic k cross times open parentheses open square brackets A close square brackets subscript 1 over open square brackets A close square brackets subscript 2 close parentheses to the power of x cross times open parentheses open square brackets B close square brackets subscript 1 over open square brackets B close square brackets subscript 2 close parentheses to the power of y end cell row cell fraction numerator begin display style bevelled fraction numerator 1 over denominator t 1 end fraction end style over denominator begin display style bevelled fraction numerator 1 over denominator t 2 end fraction end style end fraction end cell equals cell open parentheses open square brackets A close square brackets subscript 1 over open square brackets A close square brackets subscript 2 close parentheses to the power of X end cell row cell fraction numerator begin display style bevelled 1 over 16 end style over denominator begin display style bevelled 1 over 8 end style end fraction end cell equals cell open parentheses fraction numerator 0 comma 01 over denominator 0 comma 02 end fraction close parentheses to the power of x end cell row cell 1 half end cell equals cell open parentheses 1 half close parentheses to the power of x end cell row cell x space end cell equals 1 end table end style  

Orde [B] pada percobaan 1 dan 3

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator v 1 over denominator v 3 end fraction end cell equals cell italic k over italic k cross times open parentheses open square brackets A close square brackets subscript 1 over open square brackets A close square brackets subscript 3 close parentheses to the power of x cross times open parentheses open square brackets B close square brackets subscript 1 over open square brackets B close square brackets subscript 3 close parentheses to the power of y end cell row cell fraction numerator begin display style bevelled fraction numerator 1 over denominator t 1 end fraction end style over denominator begin display style bevelled fraction numerator 1 over denominator t 3 end fraction end style end fraction end cell equals cell italic k over italic k cross times open parentheses open square brackets A close square brackets subscript 1 over open square brackets A close square brackets subscript 3 close parentheses to the power of x cross times open parentheses open square brackets B close square brackets subscript 1 over open square brackets B close square brackets subscript 3 close parentheses to the power of y end cell row cell fraction numerator begin display style bevelled fraction numerator 1 over denominator t 1 end fraction end style over denominator begin display style bevelled fraction numerator 1 over denominator t 3 end fraction end style end fraction end cell equals cell open parentheses open square brackets B close square brackets subscript 1 over open square brackets B close square brackets subscript 3 close parentheses to the power of y end cell row cell fraction numerator begin display style bevelled 1 over 16 end style over denominator begin display style bevelled 1 fourth end style end fraction end cell equals cell open parentheses fraction numerator 0 comma 3 over denominator 0 comma 6 end fraction close parentheses to the power of y end cell row cell 1 fourth end cell equals cell open parentheses 1 half close parentheses to the power of y end cell row cell y space end cell equals 2 end table end style 

Orde reaksi total = 3

persamaan laju reaksinya adalah begin mathsize 14px style r space equals space italic k italic space open square brackets A close square brackets open square brackets B close square brackets squared end style

Jadi, jawaban yang benar adalah C. 

 

2rb+

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