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Pada reaksi 100 mL larutan Pb left parenthesis NO subscript 3 right parenthesis subscript 2 0,4 M dan 100 mL larutan straight K subscript 2 CO subscript 3 0,4 M jika Ksp PbCO subscript 3 equals 7 comma 4.10 to the power of negative 4 end exponent , massa zat yang mengendap adalah ...

(Ar Pb = 207, C = 12, O = 16, K = 39)

  1. 56,67 gram

  2. 10,68 gram

  3. 5,34 gram

  4. 2,67 gram

  5. 1,068 gram

D. Ayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Pembahasan

Pb left parenthesis NO subscript 3 right parenthesis subscript 2 space space space space space space space space space space space space plus space space space space space straight K subscript 2 CO subscript 3 space space space rightwards arrow space space space space space space space PbCO subscript 3 plus 2 KNO subscript 3  straight M equals 0 comma 4 straight m cross times 100 mL space space space space space 0 comma 4 straight m cross times 100 mL  space space space space equals 40 space mmol space space space space space space space space space space space space space equals 40 space mmol  straight R equals 40 mmol space space space space space space space space space space space space space space space space space space space 40 space mmol space space space space space space space space space 40 space mmol space space space space space 80 space mmol  top enclose straight S equals negative space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space minus space space space space space space space space space space space space space space 40 space mmol space space space space space 80 space mmol space space space end enclose

Karena diketahui Ksp PbCO3, maka massa yang mengendap kemungkinan besar adalah PbCO3. Mmol sisa untuk PbCO3 adalah 40 mmol.

Mol space PbCO subscript 3 equals fraction numerator gram space PbCO subscript 3 over denominator Mr end fraction  4 cross times 10 to the power of negative 2 end exponent space mol equals fraction numerator gram space PbCO subscript 3 over denominator 267 end fraction  gram space PbCO subscript 3 equals 4 cross times 10 to the power of negative 2 end exponent mol cross times 267 equals 10 comma 68 space gram

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Ke dalam 100 mL larutan Ba(NO3​), 0,01 M ditambahkan 100 mL larutan Na2​CrO4​ 0,01 M. Jika Ksp: Ba(NO3​)=2×10−10, massa zat yang mengendap adalah .... (Ar: Ba = 137, Cr = 52 : O = 16)

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