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Pertanyaan

Nyatakan akar bilangan berikut dalarn bentuk bilangan berpangkat ! e. 4 81 a 9 b 6 ​ f. 3 x − y ​ g. 5 x − 6 y 7 ​

Nyatakan akar bilangan berikut dalarn bentuk bilangan berpangkat !

e.
f.
g.

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D. Nuryani

Master Teacher

Mahasiswa/Alumni Universitas Padjadjaran

Jawaban terverifikasi

Jawaban

, , dan .

Error converting from MathML to accessible text., cube root of x minus y end root equals open parentheses x minus y close parentheses to the power of 1 third end exponent, dan Error converting from MathML to accessible text..

Pembahasan

Ingatlah, untuk sembarang bilangan dengan , berlaku: dengan . Ingat juga, sifat-sifat bilangan berpangkat berikut. Berdasarkan hal-hal di atas, maka: e) f) g) Dengan demikian, , , dan .

Ingatlah, untuk sembarang bilangan a dengan a not equal to 0, berlaku:

n-th root of a to the power of m end root equals a to the power of m over n end exponent

dengan n not equal to 0.

Ingat juga, sifat-sifat bilangan berpangkat berikut.

left parenthesis straight i right parenthesis space open parentheses a cross times b close parentheses to the power of m equals a to the power of m cross times b to the power of m left parenthesis ii right parenthesis space open parentheses a to the power of m close parentheses to the power of n equals a to the power of m cross times n end exponent

Berdasarkan hal-hal di atas, maka:

e)

table attributes columnalign right center left columnspacing 0px end attributes row cell fourth root of 81 a to the power of 9 b to the power of 6 end root end cell equals cell open parentheses 81 a to the power of 9 b to the power of 6 close parentheses to the power of 1 fourth end exponent end cell row blank equals cell open parentheses 3 to the power of 4 close parentheses to the power of 1 fourth end exponent times open parentheses a to the power of 9 close parentheses to the power of 1 fourth end exponent times open parentheses b to the power of 6 close parentheses to the power of 1 fourth end exponent end cell row blank equals cell 3 to the power of 4 cross times 1 fourth end exponent times a to the power of 9 cross times 1 fourth end exponent times b to the power of 6 cross times 1 fourth end exponent end cell row blank equals cell 3 a to the power of 9 over 4 end exponent b to the power of 6 over 4 end exponent end cell row blank equals cell 3 a to the power of 9 over 4 end exponent b to the power of 3 over 2 end exponent end cell end table

f)

cube root of x minus y end root equals open parentheses x minus y close parentheses to the power of 1 third end exponent

g)

table attributes columnalign right center left columnspacing 0px end attributes row cell square root of 5 x to the power of negative 6 end exponent y to the power of 7 end root end cell equals cell open parentheses 5 x to the power of negative 6 end exponent y to the power of 7 close parentheses to the power of 1 half end exponent end cell row blank equals cell open parentheses 5 close parentheses to the power of 1 half end exponent times open parentheses x to the power of negative 6 end exponent close parentheses to the power of 1 half end exponent times open parentheses y to the power of 7 close parentheses to the power of 1 half end exponent end cell row blank equals cell 5 to the power of 1 half end exponent times x to the power of negative 6 cross times 1 half end exponent times y to the power of 7 over 2 end exponent end cell row blank equals cell 5 to the power of 1 half end exponent x to the power of negative 3 end exponent y to the power of 7 over 2 end exponent end cell end table
 

Dengan demikian, Error converting from MathML to accessible text., cube root of x minus y end root equals open parentheses x minus y close parentheses to the power of 1 third end exponent, dan Error converting from MathML to accessible text..

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