Pertanyaan

Nilai x → 3 lim ( x − 3 2 − x + 1 ) = …

Nilai $x \to 3 lim (\frac{2 - x + 1}{x - 3}) = \dots$

N. Puspita

Master Teacher

Jawaban terverifikasi

Jawaban

hasil dari .

hasil dari $limit as x rightwards arrow 3 of open parentheses fraction numerator 2 minus square root of x plus 1 end root over denominator x minus 3 end fraction close parentheses equals negative 1 fourth$ .

Pembahasan

Dengan demikian, hasil dari .

$limit as x rightwards arrow 3 of open parentheses fraction numerator 2 minus square root of x plus 1 end root over denominator x minus 3 end fraction close parentheses equals limit as x rightwards arrow 3 of open parentheses fraction numerator 2 minus square root of x plus 1 end root over denominator x minus 3 end fraction cross times fraction numerator 2 plus square root of x plus 1 end root over denominator 2 plus square root of x plus 1 end root end fraction close parentheses equals limit as x rightwards arrow 3 of open parentheses fraction numerator 4 minus open parentheses x plus 1 close parentheses over denominator open parentheses x minus 3 close parentheses open parentheses 2 plus square root of x plus 1 end root close parentheses end fraction close parentheses equals limit as x rightwards arrow 3 of open parentheses fraction numerator 4 minus x minus 1 over denominator open parentheses x minus 3 close parentheses open parentheses 2 plus square root of x plus 1 end root close parentheses end fraction close parentheses equals limit as x rightwards arrow 3 of open parentheses fraction numerator 3 minus x over denominator open parentheses x minus 3 close parentheses open parentheses 2 plus square root of x plus 1 end root close parentheses end fraction close parentheses equals limit as x rightwards arrow 3 of open parentheses fraction numerator negative open parentheses x minus 3 close parentheses over denominator open parentheses x minus 3 close parentheses open parentheses 2 plus square root of x plus 1 end root close parentheses end fraction close parentheses equals limit as x rightwards arrow 3 of open parentheses fraction numerator negative 1 over denominator open parentheses 2 plus square root of x plus 1 end root close parentheses end fraction close parentheses equals fraction numerator negative 1 over denominator 2 plus square root of 3 plus 1 end root end fraction equals fraction numerator negative 1 over denominator 2 plus 2 end fraction equals negative 1 fourth$

Dengan demikian, hasil dari $limit as x rightwards arrow 3 of open parentheses fraction numerator 2 minus square root of x plus 1 end root over denominator x minus 3 end fraction close parentheses equals negative 1 fourth$ .