Iklan

Pertanyaan

x → − 2 lim ​ 2 − 4 + x + x 2 ​ x + 1 ​ = ...

 ...

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

02

:

04

:

35

:

32

Iklan

E. Dwi

Master Teacher

Mahasiswa/Alumni Universitas Sriwijaya

Jawaban terverifikasi

Jawaban

nilai dari adalah .

nilai dari limit as x rightwards arrow negative 2 of space fraction numerator x plus 1 over denominator 2 minus square root of 4 plus x plus x squared end root end fraction adalah fraction numerator 2 plus square root of 6 over denominator 2 end fraction.

Pembahasan

Nilai dari . Jadi, nilai dari adalah .

Nilai dari limit as x rightwards arrow negative 2 of space fraction numerator x plus 1 over denominator 2 minus square root of 4 plus x plus x squared end root end fraction.

table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as x rightwards arrow negative 2 of space fraction numerator x plus 1 over denominator 2 minus square root of 4 plus x plus x squared end root end fraction end cell row blank equals cell limit as x rightwards arrow negative 2 of space fraction numerator x plus 1 over denominator 2 minus square root of 4 plus x plus x squared end root end fraction cross times fraction numerator 2 plus square root of 4 plus x plus x squared end root over denominator 2 plus square root of 4 plus x plus x squared end root end fraction end cell row blank equals cell limit as x rightwards arrow negative 2 of space fraction numerator open parentheses x plus 1 close parentheses open parentheses 2 plus square root of 4 plus x plus x squared end root close parentheses over denominator 4 minus 4 minus x minus x squared end fraction end cell row blank equals cell limit as x rightwards arrow negative 2 of space fraction numerator open parentheses x plus 1 close parentheses open parentheses 2 plus square root of 4 plus x plus x squared end root close parentheses over denominator negative x open parentheses x plus 1 close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow negative 2 of space fraction numerator open parentheses 2 plus square root of 4 plus x plus x squared end root close parentheses over denominator negative x end fraction end cell row blank equals cell fraction numerator open parentheses 2 plus square root of 4 plus open parentheses negative 2 close parentheses plus open parentheses negative 2 close parentheses squared end root close parentheses over denominator negative open parentheses negative 2 close parentheses end fraction end cell row blank equals cell fraction numerator 2 plus square root of 4 minus 2 plus 4 end root over denominator 2 end fraction end cell row blank equals cell fraction numerator 2 plus square root of 6 over denominator 2 end fraction end cell end table 

Jadi, nilai dari limit as x rightwards arrow negative 2 of space fraction numerator x plus 1 over denominator 2 minus square root of 4 plus x plus x squared end root end fraction adalah fraction numerator 2 plus square root of 6 over denominator 2 end fraction.

Buka akses jawaban yang telah terverifikasi

lock

Yah, akses pembahasan gratismu habis


atau

Dapatkan jawaban pertanyaanmu di AiRIS. Langsung dijawab oleh bestie pintar

Tanya Sekarang

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

1

Iklan

Tanya ke AiRIS

Yuk, cobain chat dan belajar bareng AiRIS, teman pintarmu!