Pertanyaan

x → − 2 lim 2 − 4 + x + x 2 x + 1 = ...

$x \to - 2 lim \frac{x + 1}{2 - 4 + x + x ^{2}} =$ ...

E. Dwi

Master Teacher

Mahasiswa/Alumni Universitas Sriwijaya

Jawaban terverifikasi

Jawaban

nilai dari adalah .

nilai dari $limit as x rightwards arrow negative 2 of space fraction numerator x plus 1 over denominator 2 minus square root of 4 plus x plus x squared end root end fraction$ adalah $fraction numerator 2 plus square root of 6 over denominator 2 end fraction$ .

Pembahasan

Nilai dari . Jadi, nilai dari adalah .

Nilai dari $limit as x rightwards arrow negative 2 of space fraction numerator x plus 1 over denominator 2 minus square root of 4 plus x plus x squared end root end fraction$ .

$table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as x rightwards arrow negative 2 of space fraction numerator x plus 1 over denominator 2 minus square root of 4 plus x plus x squared end root end fraction end cell row blank equals cell limit as x rightwards arrow negative 2 of space fraction numerator x plus 1 over denominator 2 minus square root of 4 plus x plus x squared end root end fraction cross times fraction numerator 2 plus square root of 4 plus x plus x squared end root over denominator 2 plus square root of 4 plus x plus x squared end root end fraction end cell row blank equals cell limit as x rightwards arrow negative 2 of space fraction numerator open parentheses x plus 1 close parentheses open parentheses 2 plus square root of 4 plus x plus x squared end root close parentheses over denominator 4 minus 4 minus x minus x squared end fraction end cell row blank equals cell limit as x rightwards arrow negative 2 of space fraction numerator open parentheses x plus 1 close parentheses open parentheses 2 plus square root of 4 plus x plus x squared end root close parentheses over denominator negative x open parentheses x plus 1 close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow negative 2 of space fraction numerator open parentheses 2 plus square root of 4 plus x plus x squared end root close parentheses over denominator negative x end fraction end cell row blank equals cell fraction numerator open parentheses 2 plus square root of 4 plus open parentheses negative 2 close parentheses plus open parentheses negative 2 close parentheses squared end root close parentheses over denominator negative open parentheses negative 2 close parentheses end fraction end cell row blank equals cell fraction numerator 2 plus square root of 4 minus 2 plus 4 end root over denominator 2 end fraction end cell row blank equals cell fraction numerator 2 plus square root of 6 over denominator 2 end fraction end cell end table$

Jadi, nilai dari $limit as x rightwards arrow negative 2 of space fraction numerator x plus 1 over denominator 2 minus square root of 4 plus x plus x squared end root end fraction$ adalah $fraction numerator 2 plus square root of 6 over denominator 2 end fraction$ .