Iklan

Pertanyaan

Nilai x → 3 lim ​ x 2 + 2 x − 15 x 2 + 7 ​ − 4 x + 4 ​ ​ = ....

Nilai  

  1. size 14px 1 over size 14px 6 

  2. size 14px 1 over size 14px 32 

  3. size 14px 16 

  4. size 14px 32 

  5. size 14px 64 

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

02

:

08

:

01

:

23

Iklan

F. Freelancer9

Master Teacher

Jawaban terverifikasi

Pembahasan

Pembahasan
lock

Jadi, jawaban yang tepat adalah B.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 3 of fraction numerator square root of x squared plus 7 end root minus square root of 4 x plus 4 end root over denominator x squared plus 2 x minus 15 end fraction end cell equals cell limit as x rightwards arrow 3 of fraction numerator open parentheses square root of x squared plus 7 end root minus square root of 4 x plus 4 end root close parentheses open parentheses square root of x squared plus 7 end root plus square root of 4 x plus 4 end root close parentheses over denominator open parentheses x plus 5 close parentheses open parentheses x minus 3 close parentheses open parentheses square root of x squared plus 7 end root plus square root of 4 x plus 4 end root close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 3 of fraction numerator open parentheses x minus 3 close parentheses open parentheses x minus 1 close parentheses over denominator open parentheses x plus 5 close parentheses open parentheses x minus 3 close parentheses open parentheses square root of x squared plus 7 end root plus square root of 4 x plus 4 end root close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 3 of fraction numerator open parentheses x minus 1 close parentheses over denominator open parentheses x plus 5 close parentheses open parentheses square root of x squared plus 7 end root plus square root of 4 x plus 4 end root close parentheses end fraction end cell row blank equals cell fraction numerator open parentheses 3 minus 1 close parentheses over denominator open parentheses 3 plus 5 close parentheses open parentheses square root of 9 plus 7 end root plus square root of 12 plus 4 end root close parentheses end fraction end cell row blank equals cell fraction numerator 2 over denominator 8 open parentheses 2 square root of 16 close parentheses end fraction end cell row blank equals cell 1 over 32 end cell row blank blank blank end table end style

Jadi, jawaban yang tepat adalah B.
 

Buka akses jawaban yang telah terverifikasi

lock

Yah, akses pembahasan gratismu habis


atau

Dapatkan jawaban pertanyaanmu di AiRIS. Langsung dijawab oleh bestie pintar

Tanya Sekarang

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

1

Karisa Amirah Naila

Pembahasan tidak menjawab soal

Iklan

Tanya ke AiRIS

Yuk, cobain chat dan belajar bareng AiRIS, teman pintarmu!