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Nilai x yang memenuhi pertidaksamaan ∣ ∣ ​ x + 2 x − 3 ​ ∣ ∣ ​ < 4 adalah ....

Nilai x yang memenuhi pertidaksamaan  adalah ....

  1. negative 11 over 3 less than space straight x space less than negative 1

  2. negative 11 over 3 less than space straight x space less than 1

  3. 1 space less than straight x less than 11 over 3

  4. straight x less than negative 11 over 3 atau space straight x greater than negative 1

  5. straight x less than negative 11 over 3 atau space straight x greater than 1

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Master Teacher

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Nilai x yang memenuhi:

begin mathsize 14px style open vertical bar fraction numerator straight x minus 3 over denominator straight x plus 2 end fraction close vertical bar less than space 4 rightwards arrow straight A space equals space straight x space minus space 3 semicolon space straight B equals space straight x space plus space 2 semicolon space straight K equals space 4  space space space space space space space space space space space space space space space space space space space space space space space space space space space space left parenthesis straight A plus space KB right parenthesis left parenthesis straight A space minus space KB right parenthesis space less than space 0 space  left parenthesis straight x space minus space 3 space plus space 4 straight x space plus space 8 right parenthesis left parenthesis straight x space minus space 3 space minus space 4 straight x space minus space 8 right parenthesis space less than space 0 space  space space space space space space space space space space space space space space space space space space space space space space space left parenthesis 5 straight x space plus space 5 right parenthesis left parenthesis negative space 3 straight x space minus space 11 right parenthesis space less than space 0 space  space space space space space space space space space space space space space space space space space space space space space space space space space left parenthesis straight x space plus space 1 right parenthesis left parenthesis negative space 3 straight x space minus space 11 right parenthesis space less than space 0 end style

Nilai x yang memenuhi : negative 11 over 3 less than space straight x space less than negative 1

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Selesaikan dan tuliskan himpunan penyelesaiannya dari PtNM berikut. a. ∣ ∣ ​ x + 2 x − 1 ​ ∣ ∣ ​ ≥ 1

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