Pertanyaan

Nilai dari x → 12 lim ( 2 x + 1 − 5 x − 12 ) = …

Nilai dari $x \to 12 lim (\frac{x - 12}{2 x + 1 - 5}) = \dots$

P. Tessalonika

Master Teacher

Mahasiswa/Alumni Universitas Negeri Medan

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah B.

Pembahasan

Oleh karena itu, jawaban yang benar adalah B.

$limit as x rightwards arrow 12 of open parentheses fraction numerator square root of x minus square root of 12 over denominator square root of 2 x plus 1 end root minus 5 end fraction close parentheses equals limit as x rightwards arrow 12 of open parentheses fraction numerator square root of x minus square root of 12 over denominator square root of 2 x plus 1 end root minus 5 end fraction cross times fraction numerator square root of x plus square root of 12 over denominator square root of x plus square root of 12 end fraction cross times fraction numerator square root of 2 x plus 1 end root plus 5 over denominator square root of 2 x plus 1 end root plus 5 end fraction close parentheses equals limit as x rightwards arrow 12 of open parentheses fraction numerator open parentheses x minus 12 close parentheses open parentheses square root of 2 x plus 1 end root plus 5 close parentheses over denominator open parentheses square root of x plus square root of 12 close parentheses open parentheses open parentheses 2 x plus 1 close parentheses minus 25 close parentheses end fraction close parentheses equals limit as x rightwards arrow 12 of open parentheses fraction numerator open parentheses x minus 12 close parentheses open parentheses square root of 2 x plus 1 end root plus 5 close parentheses over denominator open parentheses square root of x plus square root of 12 close parentheses open parentheses 2 x minus 24 close parentheses end fraction close parentheses equals limit as x rightwards arrow 12 of open parentheses fraction numerator open parentheses x minus 12 close parentheses open parentheses square root of 2 x plus 1 end root plus 5 close parentheses over denominator open parentheses square root of x plus square root of 12 close parentheses open parentheses 2 open parentheses x minus 12 close parentheses close parentheses end fraction close parentheses equals limit as x rightwards arrow 12 of open parentheses fraction numerator open parentheses square root of 2 x plus 1 end root plus 5 close parentheses over denominator 2 open parentheses square root of x plus square root of 12 close parentheses end fraction close parentheses equals fraction numerator square root of 2 open parentheses 12 close parentheses plus 1 end root plus 5 over denominator 2 open parentheses square root of 12 plus square root of 12 close parentheses end fraction equals fraction numerator square root of 25 plus 5 over denominator 2 open parentheses 2 square root of 12 close parentheses end fraction equals fraction numerator 5 plus 5 over denominator 4 square root of 4 cross times 3 end root end fraction equals fraction numerator 10 over denominator 8 square root of 3 end fraction equals fraction numerator 5 over denominator 4 square root of 3 end fraction cross times fraction numerator square root of 3 over denominator square root of 3 end fraction equals fraction numerator 5 over denominator 4 cross times 3 end fraction square root of 3 equals 5 over 12 square root of 3$

Oleh karena itu, jawaban yang benar adalah B.