Pertanyaan

Nilai dari x → ∞ l im ( ( ( 4 x − 3 ) ( 9 x + 4 ) ) − 6 x + 1 ) = ...

Nilai dari $x \to \infty l im (((4 x - 3) (9 x + 4)) - 6 x + 1) = ...$

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K. Putri

Master Teacher

Mahasiswa/Alumni Universitas Pendidikan Ganesha

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Pembahasan

$stack l i m with x rightwards arrow infinity below space square root of open parentheses 4 x minus 3 close parentheses open parentheses 9 x plus 4 close parentheses end root minus 6 x plus 1 equals stack l i m with x rightwards arrow infinity below space square root of open parentheses 4 x minus 3 close parentheses open parentheses 9 x plus 4 close parentheses space end root minus space square root of open parentheses 6 x minus 1 close parentheses squared end root equals stack l i m with x rightwards arrow infinity below space square root of 36 x squared minus 11 x minus 12 end root minus square root of 36 x squared minus 12 x plus 1 end root equals fraction numerator negative 11 plus 12 over denominator 36 end fraction equals 1 over 12$

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$\style{font-size:14px}{\mathrm{Nilai}}\style{font-size:14px}\;\underset{\style{font-size:14px}{\mathrm x}\style{font-size:14px}\rightarrow\style{font-size:14px}\infty}{\style{font-size:14px}\lim}\left(\sqrt{\style{font-size:14px}4\style{font-size:14px}{\mathrm x}^\style{font-size:14px}2\style{font-size:14px}\;\style{font-size:14px}+\style{font-size:14px}\;\style{font-size:14px}3\style{font-size:14px}{\mathrm x}\style{font-size:14px}\;\style{font-size:14px}+\style{font-size:14px}\;\style{font-size:14px}4}\style{font-size:14px}\;\style{font-size:14px}-\style{font-size:14px}\;\style{font-size:14px}2\style{font-size:14px}{\mathrm x}\style{font-size:14px}\;\style{font-size:14px}+\style{font-size:14px}1\right)\style{font-size:14px}\;\style{font-size:14px}=\style{font-size:14px}\;\style{font-size:14px}.\style{font-size:14px}.\style{font-size:14px}.\style{font-size:14px}.$

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