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Nilai dari x → ∞ lim ​ 4 x 2 + 8 ​ − x 2 + 1 ​ − x 2 + x ​ = ...

Nilai dari  

  1. begin mathsize 14px style 5 over 2 end style 

  2. begin mathsize 14px style 2 end style 

  3. begin mathsize 14px style 3 over 2 end style 

  4. begin mathsize 14px style 1 end style 

  5. begin mathsize 14px style 1 half end style 

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M. Robo

Master Teacher

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Pembahasan

Ingat kembali rumus limit berikut : Maka: Penyelesaian bagian pertama : Penyelesaian bagian kedua : Penyelesaian bagian ketiga :

Ingat kembali rumus limit berikut :

limit as x rightwards arrow infinity of open parentheses square root of a x squared plus b x plus c end root space minus square root of p x squared plus q x plus r end root close parentheses equals fraction numerator left parenthesis b minus q right parenthesis over denominator left parenthesis 2 square root of a right parenthesis end fraction  

Maka:

limit as x rightwards arrow infinity of left parenthesis square root of 4 x squared plus 8 x end root minus 2 x plus x minus square root of x squared plus 1 plus x end root minus square root of x squared plus 3 x end root equals limit as x rightwards arrow infinity of open parentheses square root of 4 x squared plus 8 x end root minus square root of left parenthesis 2 x right parenthesis squared end root plus square root of x squared end root minus square root of x squared plus 1 end root plus square root of x squared end root minus square root of x squared plus 3 x end root close parentheses  

Penyelesaian bagian pertama :

limit as x rightwards arrow infinity of left parenthesis square root of 4 x squared plus 8 x end root minus square root of 2 x squared end root right parenthesis equals limit as x rightwards arrow infinity of left parenthesis square root of 4 x squared plus 8 x end root minus square root of 4 x squared end root equals fraction numerator 8 minus 0 over denominator 2 square root of 4 end fraction equals 8 over 4 equals 2    

Penyelesaian bagian kedua :

limit as x rightwards arrow infinity of square root of x squared end root minus square root of x squared plus 1 end root equals fraction numerator 0 minus 0 over denominator 2 square root of 1 end fraction space equals 0  

Penyelesaian bagian ketiga :

limit as x rightwards arrow infinity of left parenthesis square root of x squared end root minus square root of x squared plus 3 x end root equals fraction numerator 0 minus 3 over denominator 2 square root of 1 end fraction space right parenthesis equals negative 3 over 2 J a d i comma space limit as x rightwards arrow infinity of space left parenthesis square root of 4 x squared plus 8 x end root minus 2 x plus x minus square root of x squared plus 1 end root plus x minus square root of x squared plus 3 x end root equals 2 plus 0 plus left parenthesis fraction numerator negative 3 over denominator 2 end fraction right parenthesis equals 1 half  

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Vrenjes Morient Can

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