Iklan

Pertanyaan

Nilai dari x → ∞ lim ​ 4 x 2 + 8 ​ − x 2 + 1 ​ − x 2 + x ​ = ...

Nilai dari  

  1. begin mathsize 14px style 5 over 2 end style 

  2. begin mathsize 14px style 2 end style 

  3. begin mathsize 14px style 3 over 2 end style 

  4. begin mathsize 14px style 1 end style 

  5. begin mathsize 14px style 1 half end style 

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

00

:

07

:

10

:

07

Klaim

Iklan

M. Robo

Master Teacher

Jawaban terverifikasi

Pembahasan

Ingat kembali rumus limit berikut : Maka: Penyelesaian bagian pertama : Penyelesaian bagian kedua : Penyelesaian bagian ketiga :

Ingat kembali rumus limit berikut :

limit as x rightwards arrow infinity of open parentheses square root of a x squared plus b x plus c end root space minus square root of p x squared plus q x plus r end root close parentheses equals fraction numerator left parenthesis b minus q right parenthesis over denominator left parenthesis 2 square root of a right parenthesis end fraction  

Maka:

limit as x rightwards arrow infinity of left parenthesis square root of 4 x squared plus 8 x end root minus 2 x plus x minus square root of x squared plus 1 plus x end root minus square root of x squared plus 3 x end root equals limit as x rightwards arrow infinity of open parentheses square root of 4 x squared plus 8 x end root minus square root of left parenthesis 2 x right parenthesis squared end root plus square root of x squared end root minus square root of x squared plus 1 end root plus square root of x squared end root minus square root of x squared plus 3 x end root close parentheses  

Penyelesaian bagian pertama :

limit as x rightwards arrow infinity of left parenthesis square root of 4 x squared plus 8 x end root minus square root of 2 x squared end root right parenthesis equals limit as x rightwards arrow infinity of left parenthesis square root of 4 x squared plus 8 x end root minus square root of 4 x squared end root equals fraction numerator 8 minus 0 over denominator 2 square root of 4 end fraction equals 8 over 4 equals 2    

Penyelesaian bagian kedua :

limit as x rightwards arrow infinity of square root of x squared end root minus square root of x squared plus 1 end root equals fraction numerator 0 minus 0 over denominator 2 square root of 1 end fraction space equals 0  

Penyelesaian bagian ketiga :

limit as x rightwards arrow infinity of left parenthesis square root of x squared end root minus square root of x squared plus 3 x end root equals fraction numerator 0 minus 3 over denominator 2 square root of 1 end fraction space right parenthesis equals negative 3 over 2 J a d i comma space limit as x rightwards arrow infinity of space left parenthesis square root of 4 x squared plus 8 x end root minus 2 x plus x minus square root of x squared plus 1 end root plus x minus square root of x squared plus 3 x end root equals 2 plus 0 plus left parenthesis fraction numerator negative 3 over denominator 2 end fraction right parenthesis equals 1 half  

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

1

Vrenjes Morient Can

Pembahasan tidak lengkap

Iklan

Pertanyaan serupa

Nilai dari x → ∞ lim ​ [ ( 3 x − 2 ) − 9 x 2 − 2 x + 5 ​ ] = ...

3

4.6

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia