Pertanyaan

Nilai dari x → 3 lim x − 3 2 − x + 1 adalah..

Nilai dari $x \to 3 lim \frac{2 - x + 1}{x - 3}$ adalah.. $\;$

8 dari 10 siswa nilainya naik

dengan paket belajar pilihan

Habis dalam

Klaim

G. Albiah

Master Teacher

Mahasiswa/Alumni Universitas Galuh Ciamis

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah A.

Pembahasan

Oleh karena itu, jawaban yang benar adalah A.

$table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as x rightwards arrow 3 of fraction numerator 2 minus square root of x plus 1 end root over denominator x minus 3 end fraction end cell row blank equals cell limit as x rightwards arrow 3 of fraction numerator 2 minus square root of x plus 1 end root over denominator x minus 3 end fraction cross times fraction numerator 2 plus square root of x plus 1 end root over denominator 2 plus square root of x plus 1 end root end fraction rightwards arrow left parenthesis kalikan space akar space sekawan right parenthesis end cell row blank equals cell limit as x rightwards arrow 3 of fraction numerator 4 minus open parentheses x plus 1 close parentheses over denominator open parentheses x minus 3 close parentheses open parentheses 2 plus square root of x plus 1 end root close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 3 of fraction numerator 3 minus x over denominator open parentheses x minus 3 close parentheses open parentheses 2 plus square root of x plus 1 end root close parentheses end fraction end cell row blank equals cell limit as x rightwards arrow 3 of fraction numerator negative left parenthesis x minus 3 right parenthesis over denominator open parentheses x minus 3 close parentheses open parentheses 2 plus square root of x plus 1 end root close parentheses end fraction rightwards arrow open parentheses faktor space pembuat space 0 over 0 space telah space habis space dibagi close parentheses end cell row blank equals cell limit as x rightwards arrow 3 of fraction numerator negative 1 over denominator 2 plus square root of x plus 1 end root end fraction end cell row blank equals cell fraction numerator negative 1 over denominator 2 plus square root of 3 plus 1 end root end fraction leftwards arrow left parenthesis x space diganti space dengan space 3 right parenthesis end cell row blank equals cell fraction numerator negative 1 over denominator 2 plus square root of 4 end fraction end cell row blank equals cell fraction numerator negative 1 over denominator 2 plus 2 end fraction end cell row blank equals cell negative 1 fourth end cell end table$

Oleh karena itu, jawaban yang benar adalah A.