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Pertanyaan

Nilai dari tan 6 0 ∘ + 2 ⋅ sin 3 0 ∘ tan 3 0 ∘ ⋅ ( cos 3 0 ∘ + sin 3 0 ∘ ) ​ − 3 ⋅ tan 3 0 ∘ − 2 ⋅ cos 6 0 ∘ 2 ⋅ sin 6 0 ∘ ⋅ ( cos 3 0 ∘ − tan 4 5 ∘ ) ​ adalah ....

Nilai dari  adalah ....

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Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah B.

jawaban yang tepat adalah B.

Pembahasan

Perhatikan tabel berikut! Berdasarkan tabel tersebut, nilai dari dapat ditentukan melalui perhitungan berikut. Dengan demikian, nilai dari adalah 12 9 − 3 ​ ​ . Jadi, jawaban yang tepat adalah B.

Perhatikan tabel berikut!
 


 

Berdasarkan tabel tersebut, nilai dari fraction numerator tan invisible function application 30 degree middle dot left parenthesis cos invisible function application 30 degree plus sin invisible function application 30 degree right parenthesis over denominator tan invisible function application 60 degree plus 2 middle dot sin invisible function application 30 degree end fraction minus sign fraction numerator 2 middle dot sin invisible function application 60 degree middle dot open parentheses cos invisible function application 30 degree minus sign tan invisible function application 45 degree close parentheses over denominator 3 middle dot tan invisible function application 30 degree minus sign 2 middle dot cos invisible function application 60 degree end fraction dapat ditentukan melalui perhitungan berikut.
 

table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator tan invisible function application 30 degree middle dot left parenthesis cos invisible function application 30 degree plus sin invisible function application 30 degree right parenthesis over denominator tan invisible function application 60 degree plus 2 middle dot sin invisible function application 30 degree end fraction minus sign fraction numerator 2 middle dot sin invisible function application 60 degree open parentheses cos invisible function application 30 degree minus sign tan invisible function application 45 degree close parentheses over denominator 3 middle dot tan invisible function application 30 degree minus sign 2 middle dot cos invisible function application 60 degree end fraction end cell row blank equals cell fraction numerator 1 third square root of 3 middle dot open parentheses 1 half square root of 3 plus 1 half close parentheses over denominator square root of 3 plus 2 middle dot 1 half end fraction minus sign fraction numerator 2 middle dot 1 half square root of 3 left parenthesis 1 half square root of 3 minus sign 1 right parenthesis over denominator 3 middle dot 1 third square root of 3 minus sign 2 middle dot 1 half end fraction end cell row blank equals cell fraction numerator 1 over 6 middle dot 3 plus 1 over 6 square root of 3 over denominator square root of 3 plus 1 end fraction minus sign fraction numerator 1 half middle dot 3 minus sign square root of 3 over denominator square root of 3 minus sign 1 end fraction end cell row blank equals cell fraction numerator 1 half plus 1 over 6 square root of 3 over denominator square root of 3 plus 1 end fraction minus sign fraction numerator 3 over 2 minus sign square root of 3 over denominator square root of 3 minus sign 1 end fraction end cell row blank equals cell fraction numerator 1 half plus 1 over 6 square root of 3 over denominator square root of 3 plus 1 end fraction middle dot fraction numerator square root of 3 minus sign 1 over denominator square root of 3 minus sign 1 end fraction minus sign fraction numerator 3 over 2 minus sign square root of 3 over denominator square root of 3 minus sign 1 end fraction middle dot fraction numerator square root of 3 plus 1 over denominator square root of 3 plus 1 end fraction end cell row blank equals cell fraction numerator open parentheses 1 half plus 1 over 6 square root of 3 close parentheses open parentheses square root of 3 minus sign 1 close parentheses over denominator 3 minus sign 1 end fraction minus sign fraction numerator open parentheses 3 over 2 minus sign square root of 3 close parentheses open parentheses square root of 3 plus 1 close parentheses over denominator 3 minus sign 1 end fraction end cell row blank equals cell fraction numerator 1 half square root of 3 minus sign 1 half plus 1 half minus sign 1 over 6 square root of 3 over denominator 2 end fraction minus sign fraction numerator 3 over 2 square root of 3 plus 3 over 2 minus sign 3 minus sign square root of 3 over denominator 2 end fraction end cell row blank equals cell fraction numerator 1 third square root of 3 over denominator 2 end fraction minus sign fraction numerator 1 half square root of 3 minus sign 3 over 2 over denominator 2 end fraction end cell row blank equals cell 1 over 6 square root of 3 minus sign open parentheses 1 fourth square root of 3 minus sign 3 over 4 close parentheses end cell row blank equals cell 1 over 6 square root of 3 minus sign 1 fourth square root of 3 plus 3 over 4 end cell row blank equals cell 3 over 4 minus sign 1 over 12 square root of 3 end cell row blank equals cell fraction numerator 9 minus sign square root of 3 over denominator 12 end fraction end cell row blank blank blank end table 

Dengan demikian, nilai dari fraction numerator tan invisible function application 30 degree middle dot left parenthesis cos invisible function application 30 degree plus sin invisible function application 30 degree right parenthesis over denominator tan invisible function application 60 degree plus 2 middle dot sin invisible function application 30 degree end fraction minus sign fraction numerator 2 middle dot sin invisible function application 60 degree middle dot open parentheses cos invisible function application 30 degree minus sign tan invisible function application 45 degree close parentheses over denominator 3 middle dot tan invisible function application 30 degree minus sign 2 middle dot cos invisible function application 60 degree end fraction adalah .

Jadi, jawaban yang tepat adalah B.

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