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Pertanyaan

Nilai dari ∫ 1 2 ​ ( 3 x 2 − 4 x + 5 ) d x = ....

Nilai dari = ....

  1. 6

  2. 5

  3. 4

  4. 3

  5. 2

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R. Diah

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

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Pembahasan

integral subscript a superscript b a x to the power of n d x equals open square brackets fraction numerator a over denominator n plus 1 end fraction x to the power of n plus 1 end exponent close square brackets subscript b superscript a equals open parentheses fraction numerator a over denominator n plus 1 end fraction b to the power of n plus 1 end exponent close parentheses minus open parentheses fraction numerator a over denominator n plus 1 end fraction a to the power of n plus 1 end exponent close parentheses  integral subscript 1 superscript 2 left parenthesis 3 x squared minus 4 x plus 5 right parenthesis d x equals left square bracket x cubed minus 2 x squared plus 5 x right square bracket subscript 1 superscript 2  equals left parenthesis left parenthesis 2 right parenthesis cubed minus 2 left parenthesis 2 right parenthesis squared plus 5 left parenthesis 2 right parenthesis right parenthesis minus left parenthesis left parenthesis 1 right parenthesis cubed minus 2 left parenthesis 1 right parenthesis squared plus 5 left parenthesis 1 right parenthesis right parenthesis  equals left parenthesis 10 right parenthesis minus left parenthesis 4 right parenthesis  equals 6

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Hasil dari ∫ 0 2 ​ 3 ( x + 1 ) ( x − 6 ) d x = ...

1

0.0

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