Pertanyaan

Nilai dari =.....

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I. Roy

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

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$D i k e t a h u i space b a h w a space n i l a i space d a r i limit as x rightwards arrow infinity of invisible function application open parentheses square root of a x squared plus b x plus c end root minus square root of a x squared plus q x plus r end root close parentheses equals fraction numerator b minus q over denominator 2 square root of a end fraction S e h i n g g a limit as x rightwards arrow infinity of invisible function application open parentheses open parentheses 2 x minus 1 close parentheses minus square root of 4 x squared minus 6 x minus 5 end root close parentheses space d a p a t space d i u b a h space k e space d a l a m space b e n t u k limit as x rightwards arrow infinity of invisible function application open parentheses square root of open parentheses 2 x minus 1 close parentheses squared end root minus square root of 4 x squared minus 6 x minus 5 end root close parentheses limit as x rightwards arrow infinity of invisible function application open parentheses square root of 4 x squared minus 4 x plus 1 end root minus square root of 4 x squared minus 6 x minus 5 end root close parentheses equals fraction numerator negative 4 minus open parentheses negative 6 close parentheses over denominator 2 square root of 4 end fraction equals fraction numerator 2 over denominator 2 open parentheses 2 close parentheses end fraction equals 1 half$

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$\style{font-size:14px}{\mathrm{Nilai}}\style{font-size:14px}\;\underset{\style{font-size:14px}{\mathrm x}\style{font-size:14px}\rightarrow\style{font-size:14px}\infty}{\style{font-size:14px}\lim}\left(\sqrt{\style{font-size:14px}4\style{font-size:14px}{\mathrm x}^\style{font-size:14px}2\style{font-size:14px}\;\style{font-size:14px}+\style{font-size:14px}\;\style{font-size:14px}3\style{font-size:14px}{\mathrm x}\style{font-size:14px}\;\style{font-size:14px}+\style{font-size:14px}\;\style{font-size:14px}4}\style{font-size:14px}\;\style{font-size:14px}-\style{font-size:14px}\;\style{font-size:14px}2\style{font-size:14px}{\mathrm x}\style{font-size:14px}\;\style{font-size:14px}+\style{font-size:14px}1\right)\style{font-size:14px}\;\style{font-size:14px}=\style{font-size:14px}\;\style{font-size:14px}.\style{font-size:14px}.\style{font-size:14px}.\style{font-size:14px}.$

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