Pertanyaan

Nilai dari = ....

-6
-4
-1
4
6

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S. Intan

Master Teacher

Mahasiswa/Alumni Institut Pertanian Bogor

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Pembahasan

$begin mathsize 14px style limit as x rightwards arrow infinity of invisible function application space open parentheses square root of 4 x squared plus 4 x minus 3 end root minus left parenthesis 2 x minus 5 right parenthesis close parentheses equals limit as x rightwards arrow infinity of invisible function application space open parentheses square root of 4 x squared plus 4 x minus 3 end root minus square root of open parentheses 2 x minus 5 close parentheses squared end root close parentheses equals limit as x rightwards arrow infinity of invisible function application space open parentheses square root of 4 x squared plus 4 x minus 3 end root minus square root of 4 x squared minus 20 x plus 25 end root close parentheses equals fraction numerator b minus q over denominator 2 square root of a end fraction equals fraction numerator 4 minus open parentheses negative 20 close parentheses over denominator 2 square root of 4 end fraction equals 24 over 4 equals 6 end style$

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