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Pertanyaan

Nilai dari ( 8 ) 3 1 ​ + ( 25 ) 2 1 ​ ( 125 ) 3 1 ​ − ( 81 ) 4 1 ​ ​ = ....

Nilai dari = ....

  1. begin mathsize 14px style 2 over 7 end style

  2. begin mathsize 14px style 2 over 4 end style

  3. begin mathsize 14px style 5 over 7 end style

  4. 1

  5. begin mathsize 14px style 8 over 7 end style

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S. Intan

Master Teacher

Mahasiswa/Alumni Institut Pertanian Bogor

Jawaban terverifikasi

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Pembahasan

begin mathsize 14px style fraction numerator left parenthesis 125 right parenthesis to the power of 1 third end exponent minus left parenthesis 81 right parenthesis to the power of 1 fourth end exponent over denominator left parenthesis 8 right parenthesis to the power of 1 third end exponent plus left parenthesis 25 right parenthesis to the power of 1 half end exponent end fraction end style
begin mathsize 14px style equals fraction numerator open parentheses 5 cubed close parentheses to the power of 1 third end exponent minus open parentheses 3 to the power of 4 close parentheses to the power of 1 fourth end exponent over denominator open parentheses 2 cubed close parentheses to the power of 1 third end exponent plus open parentheses 5 squared close parentheses to the power of 1 half end exponent end fraction  equals fraction numerator 5 minus 3 over denominator 2 plus 5 end fraction  equals 2 over 7 end style

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Hasil dari 8 4 5 ​ 2 4 3 ​ × 4 3 2 ​ ​ adalah ...

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