Pertanyaan

Nilai adalah ....

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S. Intan

Master Teacher

Mahasiswa/Alumni Institut Pertanian Bogor

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Pembahasan

$begin mathsize 14px style limit as straight x rightwards arrow straight infinity of invisible function application space open parentheses square root of 9 straight x squared plus 6 straight x minus 2 end root minus 3 straight x plus 1 close parentheses equals limit as x rightwards arrow infinity of invisible function application space open parentheses square root of 9 x squared plus 6 x minus 2 end root minus open parentheses 3 x minus 1 close parentheses close parentheses equals limit as x rightwards arrow infinity of invisible function application space open parentheses square root of 9 x squared plus 6 x minus 2 end root minus square root of 9 x squared minus 6 x plus 1 end root close parentheses equals fraction numerator 6 minus left parenthesis negative 6 right parenthesis over denominator 2 square root of 9 end fraction equals 12 over 6 equals 2 end style$

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